 Hello and welcome to the session. In this session we discuss the following question let's say draw a line segment PQ equal to 5 centimeters take a point R on PQ such that P R is equal to 3 centimeters from R draw R as perpendicular to PQ. Let's move on to the solution now. We will do this construction step by step. So first of all we draw a line segment PQ equal to 5 centimeters. This is the line segment PQ equal to 5 centimeters. In the next step we mark a point R on the line segment PQ such that we have P R equal to 3 centimeters. So this is the point R such that we have this P R equal to 3 centimeters. Now next from the point R we need to draw a perpendicular RS to PQ. So next step of construction would be with R as the center and any radius draw a semicircle to intersect PQ at A and B. So we have drawn this semicircle it intersects line segment PQ at points A and B. Then in the next step with A as the center and radius more than half of AB we draw an arc. So taking A as the center and radius more than half of AB we have drawn this arc. In the same way with B as the center and radius more than half of AB we draw another arc taking the previous arc at point S. So we have drawn this arc intersecting the previous arc and this point of intersection of the two arcs is S. So in the next step we join RS so we have joined RS and we get RS perpendicular to PQ. So with this we complete the session hope you have understood the solution of this question.