 I'm not sure number-wise, but I'm going to say it out loud, okay? So it says which of the following is the best synthesis of cyclohexene from cyclohexene? But anyways, what can you all think of a synthesis of going from here to here? I'll tell you what I would do, okay? The first step, everybody should be able to tell me this thing. Can anybody tell me this one? Anybody know any reactions with alkanes? What is it? Oh, the BR2? The BR2. What else do you need? Life. Life. Okay, and what's that going to give us? Anybody? The R2. Yeah, the R. And then to get that, what kind of reaction are we doing? Can anybody think of that like the name of the reaction? We're removing something, so it's an elimination reaction. So what would be a good way to do maybe an E2 reaction? Do you remember what we needed for E2 reaction? I won't look at you, no pressure. Your solvents would be more large. Oh, okay, yeah, so like a sterically encumbered molecule you want to do. Okay, so let's say for the solvent, we'll do tert-butanol, right? Isn't the same as what they were doing on the thing. But I'll show you the mechanism of this, and it's the same mechanism. It's just this is going to be a little different. Now what would you need? This would actually remove it, right? This would be the solvent. What would you need to remove it, do you remember? The this, but the conjugate base of it. So you need sodium tert-butanol, okay? That's going to be the active ingredient. That would do it, that's the synthesis. And this one I think they're using instead of this, which is actually a better reagent for the elimination. They're doing KOH and H2O, which would also, okay? But let's go over the mechanism since that's what we wanted to do, okay? We're going to go over both of these mechanisms. So the first step, we're going to take this and we're going to take Br2 and we're going to break the bond homolytically with light to make Br. Which is just a bromine atom, but it's a radical. Another Br. like that, okay? So those Br. are very reactive and what they'll do to try to make themselves not a radical is they're going to extract hydrogens from the alkane group. So what's going to happen? And I know you know this mechanism like the back of your hand so you don't have to write this thing down, although you could help me out if you wanted to. So we're going to get that now. We're also going to have that floating around in there because of this stuff, right? But now what's going to happen? Is another Br2 molecule like that? That's going to give us our final product that we're looking at. Plus another Br. We're going to go back and do that first reaction. Okay? So that, remember what we said was the intermediate in this reaction. Okay? So that's how you get to that. Okay? I'm going to erase the first part. I know you all know that so well. So if you don't go back to this video, it's being recorded. Okay? So let's just do the second step and we'll use sodium tert-butoxide since that was what was said by one of the students in here. So let's use that one. But again, for the V2 reaction, the elimination, the KOH would do the same thing, the OH-. Okay? So remember, we have a proton there. Okay? So I didn't turn to the top side. If you want to, just think of this as an H. Okay? It'll do the same thing as hydroxide. So is this still on camera? Okay. I saw you looking up there. Yeah, I was trying to check in on you. No, yeah. Okay. I was wondering, it must have been either it was probably off-camera or maybe it was bullet-keeping that it was going to die. So that's how you do the second step. Okay? So in other words, if it was the KOH, just like in that one when we said sodium tert-butoxide, we didn't show the sodium anywhere. Right? If it's KOH, it would just be like that. Okay? So the side product, of course, would be H2O of that one and for the other one. Does that make sense? Wonderful. Any questions on that? Good job, guys.