 Hi and how are you all today? My name is Priyanka and the question says in figure 9.23 E is any point on median AD of a triangle ABC. Show that area of ABE is equal to A, area of ABE is equal to area of ACE. Now this is the figure 9.23 which we need to refer where E is any point on median AD of triangle ABC. We need to equate the area of ABE that means this triangle with the area of ACE that means this triangle. So let us proceed on with our solution here. In triangle ABC we know that AD is the median of this triangle right. Now therefore we can say that area of triangle ABD is equal to area of triangle ACD. Let this be the first equation and the reason is because median divides a triangle into two triangles of equal area. As we know that a median divides the full triangle into two triangles of equal area. Also X, E is any point on this median AD. So therefore ED will also be the median of this triangle. So in triangle EBDC, ED is the median right. So for this small triangle this will also be the median. So we can say that therefore area of EBD will be equal to area of EDC because of the same reason because median divides a triangle into triangles of equal area. Let this be the second equation. On subtracting the second equation from the first we have area of triangle ABD this whole triangle. If from this area this whole triangles area we subtract this area we are left with this area right. So on subtracting area of EBD is equal to area of ADC minus area of EDC that is equal to area of ABE is equal to area on subtracting this area from this full triangle. We are left with this area that is ECE. So this was the point that was needed to be proved. So this completes our question. So hence we proved the given question. Hope you enjoyed the session. Take care and bye for now.