 Hello and welcome to the session. In this session we will discuss the parallelogram construction when two sides and height are given. Suppose we need to construct parallelogram with its two sides of measure 5 cm, 3 cm, 3 cm. So consider this rough figure of the parallelogram which we have to construct with its two sides say PQ and QR of measure 5 cm and 4 cm respectively and the height is given as, that is, Qt is given as 3 cm. So to do this construction we need to follow certain steps of construction that would be draw PQ equal to 3 m. So we have drawn a straight line PQ of measure 5 cm. In the next step we draw 2x drawn perpendicular to PQ. Now as the height of the parallelogram is Qt of measure 3 cm, so P centre is the radius Qx at the point T. So this is the arc that we have drawn taking Q at the centre and radius equal to 3 cm. At this point of intersection of this arc and Qx we point T. So we now have Qt of measure 3 cm. Now in the next step we draw yz equal to PQ through the point yz parallel to PQ through the point T. As we know that in a parallelogram opposite sides are equal, so as PQ is a measure 5 cm, so rs would also be a measure 5 cm and as Qr is a measure 4 cm, so Px would also be a measure 4 cm and Q as centres in turn and radius equal to 10 cm. So we have drawn this arc taking Pst centre and radius equal to 4 cm such that it cuts yz at the point S. In this way we will draw another arc on yz through the point Q taking 4 cm as the radius. At this point of intersection of this arc with yz be point R, we join as we get the parallelogram PQ rs in which PQ is of measure 5 cm, Qr is of measure 4 cm and Qt is of measure that is the height of the parallelogram is of 3 cm. C required parallelogram. See the construction of the parallelogram when it's height one side and one diagonal are given to us. We consider the same parallelogram in which PQ is of measure 5 cm that is one side of the parallelogram is given to us, then its height is given as which is Qt, it is 3 cm and one diagonal which is Pr is given to us at centimeters. Construction in which we are given the height one side and one diagonal of a parallelogram the height is given. Step one, step two, step three and step four would be the same and height of the parallelogram Q of measure 5 cm and the height of the parallelogram given by Qt of measure 3 cm that in the construction would be we cut an arc in center and radius equal to 8 cm that this arc intersect yz parallelogram of measure 8 cm. So then we join Pr are equal to be of measure yz and radius equal to 5 cm. Now this kind of intersection of the arc and yz in this way we can construct a parallelogram when it's one side one diagonal and height is given to us. We discuss the parallelogram construction when height of the parallelogram one side and one angle are given to us. The gram Pqrs in which its side Pq is of measure 5 cm, its height Qt is given as 3 cm and the Qps says of measure 50 degrees. So these steps one, two, three and four side of the parallelogram its height which is of measure 5 cm and we have drawn the height Qt of measure 3 cm of the parallelogram Pqrs of measure 50 degrees. Next step would be this angle Qps of measure 50 degrees. Next parallelogram are equal 20 meters so rs would also be of measure 5 cm are taking s at the center and radius equal to 5 cm and we get Pq given to us given to us.