 Hi and welcome to the session. Let us discuss the following question. The question says, if the triangle ABC in question 7 above is revolved above the side 5 centimeters, then find the volume of the solids are obtained and also the ratio of the volumes of the two solids obtained in question 7 and 8. Let's now begin with this illusion. In question 7 we are given a right triangle ABC whose sides are 12 centimeters, 5 centimeters and 13 centimeters. In this question this triangle ABC is revolved above the side BC. We know that the solid generated by the rotation of a right angle triangle about one of the sides containing the right angle is called a right circular cone. Now here also the right triangle ABC is revolved above the side BC. So on revolving side BC equals to 5 centimeters of triangle ABC we will get a cone like this whose height is 5 centimeters. And base radius is 12 centimeters. Now we will find the volume of cone generated. The volume of cone generated is equal to 1 by 3 pi r square h. Now here radius that is r is equal to 12 centimeters and height that is h is equal to 5 centimeters. By substituting the values of r and h we get 1 by 3 into pi into 12 into 12 into 5 centimeter q. On cancelling 12 by 3 we get 4. So this is equal to 240 pi centimeter q. Now we have to find the ratio of the volumes of the two solids obtained in question 7 and question 8. Volume of solid obtained in question 7 is 100 pi centimeter q and volume of solid obtained in this question is 240 pi centimeter q. So ratio of volumes two solids obtained in question 7 and 8 is equal to 100 pi upon 240 pi pi and pi cancels off on cancelling 100 by 240. We get 5 by 12. So ratio of volume of two solids obtained in question 7 and question 8 is 5 is to 12. Hence our required answers are 240 pi centimeter q and 5 is to 12. So this completes the section. Bye and take care.