 Hi and how are you all today? The question says 8% of people in a group are left handed. What is the probability that 2 or more of a random sample of 25 from the group are left handed? So here in this question we are given the value of P as 8% that is 8 by 100. And we are given the number of people in the group as 25. So let us find out the value of lambda first. So it is n into P that is 25 into 8% which gives us the answer as now probability that 2 or more people from this group are left handed is equal to when P probability that x is greater than 2 isn't it? And probability that x is greater than 2 can be found out by subtracting probability of x is less than equal to 1 from 1 as the sum of all the probabilities will be equal to 1. This further implies 1 minus bracket probability that x is equal to 1 plus probability of x is equal to 0. We will be finding it out. We can write it as like this also. Now we have 1 minus now probability of 1 can be written as 2 raised to the power 1 into e raised to the power minus 2 upon 1 factorial plus 2 raised to the power 2 into e raised to the power minus 2 upon 0 factorial. Now in the question we are given to use the value of minus e raised to the power minus 2 as 0.135. So using it here we have 1 minus 2 into 0.135 upon 1 minus 2 into 0.135 upon 1. That is further equal to 1 minus its value after multiplying is 0.27 plus 0.135. So we have after simplifying 1 minus 0.405 which is further equal to 0.595. So the answer to this question is 0.595. This is the probability that 2 or more people of a random sample of 25 from the group R left-handed. This ends the session. Hope you understood it well. Enjoy it. Bye for now.