 Hello, I'm Professor Stephen Nesheba, and I'm going to show you how to build some molecules having to do with Lewis acid-base reaction. To get started, I'm, I'm, I press the inorganic menu over here. I want to choose nitrogen, and there's that. And then the configuration that I want is this tetrahedral arrangement over with only three things bonded. So that would be, that would be that molecule. And the same thing for BF3, I'll show you that one. I need to choose boron there. But I happen to know that boron is a trigonal planar molecule, so I'm just going to click that there. The other thing is that in order to get fluorines on here, here they, there's going to default to hydrogens. So I'm going to choose fluorine over here. And also, I just want to make a single bond, you know, to it. So I'm going to do that. And so I'm going to put fluorine there, fluorine there, and fluorine there. And after this, with both of these, you'll do the usual thing, which is going here to the build menu, and, and so on. So the only other piece of this that I think you need to know about is how to build the adduct. And the way we're going to do that is I'm going to again start with the tetrahedral arrangement, but with four things coming off. Once again, with ammonia, here we go. And so what that does is it allows me to connect something right there. And the thing that I'm going to connect is a boron, also in that arrangement, right there. Okay, so now we have NH3BH3. And the only thing that remains is replacing those hydrogens with fluorines, which I'm going to do in a similar way to what we did before. Just have fluorine with a single bond there, and there, and there. And, and so we are good to go. Now it's usually good to try to do a minimization on this first. So I'm going to try to do that. And, and so now we, I think we're good to start a calculation, an electronic structure calculation, just as, as, as, as usual.