 Hello and welcome to the session. In this session we discussed the following question which says, in the given figure, Pm is a tangent to the circle and Pa is equal to Am, so that triangle Pmb is isosceles. Before we move on to the solution, let's discuss the alternate segment property according to which we have straight line which is a circle from the point of contact the tangent respectively equal to the angles in the alternate segments. This is the key idea that we use in this question. Let's move on to the solution now. This is the figure given to us in which we have equal to Am, Pa, these two are equal and we also have angle m is equal to, we are supposed to prove Vj, Vm, same triangle Pmb and we are supposed to prove that this triangle is isosceles triangle, a is equal to m will be equal to angle Amp, so these two angles are equal therefore equal to angle Amp equal to and we call the alternate segment property in which we have that if a straight line touches the circle those between the tangent and the curve are respectively equal to the angles in the alternate segments. Now the figure we have from the point of contact between this tangent Pm and we call Amp would be equal to the angle in the alternate segment using the this means that angle equal to angle Amp is of Eb is equal to Bp and both are of measure x that mv is equal to mp to be equal therefore we say that triangle is what we are supposed to prove that triangle Pmb is isosceles triangle. So this completes the session but you have understood the solution of this question.