 Hello and welcome to the session I am Deepika here. Let's discuss the question which says integrate the following function under root of form minus x square. Let us first understand a special type of standard integral which is integral of the root of a square minus x square dx is equal to 1 by 2 x into under root of a square minus x square plus a square upon 2 sin inverse x upon a plus c. So this is a key idea behind the question. We will take the help of this key idea to solve the above question. So let's start the solution. Now we have to integrate the function under root of form minus x square. Another key idea we have integral of under root of a square minus x square dx is equal to 1 by 2 x into under root of a square minus x square plus a square upon 2 sin inverse x upon a plus c is equal to 2. Therefore integral of a square minus x square dx is equal to 1 over 2 into x under root of a square which is 2 square minus x square plus 2 square upon 2 sin inverse x upon 2 plus c. And this is equal to 1 by 2 to under root of 4 minus x square plus inverse x upon 2 plus c. The answer for the above question is 1 plus x square plus 2 sin inverse x upon 2 plus c. It is clear to you. Bye and take care.