 Hi and welcome to the session. I'm Kanika and I'm going to help you to solve the following question. The question says a conical tent is 10 meters high and the radius of its base is 24 meters. Fine, first part is slant height of the tent and second part is cost of the canvas required to make the tent if the cost of 1 meter square of canvas is rupees 70. Before solving this question, we should know that slant height of the coat that is L is equal to square root of h square plus r square and we should also know that curve surface area of a coat is equal to pi rL where r is the base radius and L is the slant height. The knowledge of this is the key idea in this question. Now, begin with the solution. In the first part, we have to find the slant height of the tent. Suppose this is the conical tent. It is given to us that its height that is h is equal to 10 meters radius of its base that is r is equal to 24 meters. We have learned in the key idea that slant height that is L is equal to square root of h square plus r square. We know the value of h and r so we can easily find it slant height. Substitute the value of h and r and this h is equal to 10 meters, r is equal to 24 meters. So this is equal to square root of 676 meters and this is equal to 26 meters. So slant height of the cone is 26 meters. This completes the first part. Let's now move on to the second part. In the second part, we have to find the cost of the canvas required to make the tent if the cost of 1 meter square canvas is rupees 17. Now we know that tent has only a curved surface. The floor of the tent is not covered by the canvas. So clearly area of the canvas is equal to curved surface area of cone. We have learned in the key idea that curved surface area of cone is equal to pi rL. Now here r is equal to 24 meters and from the first part we know that L is equal to 26 meters. So now by substituting the values we get 22 by 7 into 24 into 26 meters square. We are given that cost of 1 meter square of canvas is rupees 17. Therefore cost of 22 by 7 into 24 into 26 meters square of canvas is rupees 17 into 22 by 7 into 24 into 26. And this is equal to rupees 1,37,280. Hence the required answer of the first part is 26 meters and for the second part is rupees 1,37,280. So this competes the session by NJKL.