 Hello friends, welcome to the session. I am Malkha. Let us examine the applicability of mean value theorem for all the three functions given in the above exercise 2. Our function is fx equal to greatest integer of x for x being the element of closed interval minus 2, 2. Now, let us start with the solution. We have given fx equal to greatest integer of x for x being the element of closed interval minus 2, 2. Now, let us check the applicability of the given function. So, for the limit x approaching to 0 from r h is fx equal to limit x approaching to 0 from r h is greatest integer of x equal to 0 that is minus 2 is less than equal to 0 is less than equal to 2. Now, limit for x approaching to 0 from l h is fx equal to limit x approaching to 0 from l h is greatest integer of x equal to minus 1. Now, this implies that limit x approaching to 0 from r h is fx is not equal to limit x approaching to 0 from l h is fx. This implies that function is not continuous x equal to 0. Therefore, since all the three conditions are not satisfied, hence mean value theorem does not hold good. Theorem does not hold good. Hope you understood the solution and enjoyed this session. Goodbye and take care.