 polymerization to give linear or cyclic compound to give linear or cyclic compound depending upon depending upon the temperature and catalyst. Three reactions we have here, first one you have now, acetylene when passed into cuprous chloride C2, C2, acetylene when passed into cuprous chloride, cuprous chloride solution, alkene when passed into cuprous chloride solution, acetylene, cuprous chloride solution containing ammonium chloride, it combines and forms vinyl acetylene, it combines and forms vinyl acetylene. So actually we take two molecules of acetylene C-H triple bond C-H and when it is treated with, C2, C2, cuprous chloride, no the copper is plus 1 oxidation, C2, C2 is plus 2, so for copper we have both of them. Oh it is the timer of this one, this is the product here is C-H double bond C-H single bond C triple bond C, this is the molecule, C-H double bond C-H single bond C triple bond C-H, you see this is, see this carbon is vinylic carbon, yes it is a vinylic position, if you attach chlorine here then vinyl chloride, so what is the vinylic position, vinylic position is this, C-H2 double bond C-H, this is vinylic carbon, if you attach chlorine here it is vinyl chloride, so at vinyl position we have acetylene, that is why it is vinyl acetylene, vinyl acetylene, right on the next line, vinyl acetylene reacts with HCl, vinyl acetylene reacts with HCl and forms 2 clodo 1,3 butadiene, 2 clodo 1,3 butadiene which is commonly known as clodoprene, it is from this we, this is a monomer, from this we will form a compound which we called as poly clodoprene, polymer of it, clodoprene what is the structure of clodoprene, see the reaction of this with HCl, this reaction is again same, addition of HCl on, ok one thing you also remember here, if you have double bond and triple bond present, this pi bond is weaker than this pi bond, right, so addition of HCl takes place on alkynes, alkynes are the better nucleophiles, so this reaction takes place here, so it forms C-H2 double bond, C-H single bond, C-Cl double bond C-H2 double bond, this is 2 clodo 1,3 butadiene which is commonly known as clodoprene, so basically it is a dimerization reaction of acetylene in presence of cuprous clodide and NH4C, dimerization reaction, ok next line write down Sir vinyl acetylene is R double bond C-H, R double bond C-H and R double bond C-H, R C-H double bond C-H, so do you know about it? Yes sir, it is not vinyl, vinylic is this, C-H2 double bond C-H, one more thing is there if you have this C-H2 single bond C-H double bond C-H2, if it is there this carbon is allylic, allylic carbon, this 2 purision you must know, this one is vinylic and this one is allylic carbon, this is benzylic, this one is benzylic purision, C-H2 C-H2 double bond C-H2 C-H2 C-H double bond C-H, this is benzylic carbon, this 2 we have a positive charge here, this is benzylic carbon, allylic carbon, which one is more stable? Sir, which one is more stable? Benzylic, benzylic, benzylic, benzylic. Benzylic, benzylic, benzylic, benzylic, benzylic, benzylic, benzylic, benzylic. Both of them have resurances, here we have more resurances. It is like this, okay this one is more stable, anyways next time write down alkyne when passed through, alkyne when passed through, a red hot ion tube, alkyne when passed through, a red hot ion tube, it forms an aromatic compound, an aromatic compound, why does it have to be red hot? Why does it have to be red hot? It is a catalyst basically, since you have an iron tube and this we are allowed to pass through, like we discussed know, depending upon the reagent and catalyst here, you get different different products. So what does it have to be like? See, just a tube. Yeah, that's what I imagined. We write it as red hot ion tube, but it's like the, you know, we have an arrangement where the reaction is taking place, okay. There we have an iron tube actually. So iron is behaving as a catalyst for this reaction. In some book it is written in the environment of iron, like this also. So why does it have to be tube, like red hot? Anything is, that's what I said. It is an iron environment. We write it as red hot tube. So you said different reagents would give me different products, like other products. We can also, we can also take copper tube here. So what would it give me? Same thing you will get. Okay. But usually the reaction is visible with iron. Copper, copper ion generally mostly. So what are different products that I get with red hot? See, first of all I get, first of all we will get vinyl acetylene. Yeah. Acetylene molecule. So that's what red hot. Yeah, that's what. The reagent is what? Acetylene? Yes. Say product is this. Why? Because the reagent is different. Yeah. Here also we have acetylene. The reagent is different. So it's like what, what other... So, okay. No, but is there anything else that gets the different red hot? No, it's not there. Okay, tell me the product in this reaction. What reagent are you using? Oh, it's like a... 1, 3, 1, 5. 1, 5, 5, 5, 5, 5, 5, 6, 7, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9. I was about to... Just take it, just take it. If the reagent is this. They are here. Okay, the chapter is done. One question is... Where did that come from? That's what we are telling. You need to write down the mechanism of this. Mechanism? Mechanism? That's not speed vibration. Tell me that. No, it's... We haven't done this question. Similar we haven't done. Exactly this question we haven't done. Similar we haven't done. The steps. And then your positive will be... See, you have a double one, right? So, in case one hydrogen come out. I'll do this. See, the first step is what? Okay. Okay, see H plus here. Okay. This is dehydrolysis, right? Dehydration of alcohol. This oxygen. We'll take this H plus. It forms H2O plus here. And then this H2O goes out. So, minus of H2O. It gives you what? We know dehydrolysis. Intermediate is what? Intermediate is what? Intermediate is what? Intermediate is what? Intermediate is the carbocation. And we have rearrangement also if it is possible. This is 3 degree. For the rearrangement possible? Yes. How? No requirement. No requirement. If you have 1, 2 hydride shifts. Hydrogen. Hydrogen. Hydrogen. This hydrogen comes over here. And it forms. Yes, so why would it do that? Because it's already C-boy here. How many? How many alpha here? 3 plus 3 plus 1 is 7. How many alpha here? Probably more than 7. Probably more than 7. 1, 2, 1, 4. Right? It's less than. It's not destabilized to hyperconjugation. But here this positive charge case resonance is destabilized. That's right. Here we have hyperconjugation. But here we have resonance. Pi sigma positive charge. Now you can write down the resonating. How it's called? It's a resonating structure. So resonating structure of this one is what? This comes over here. Positive charge. And this C is 3. Why did we do this? You can ask me why? Carbon, this positive charge is destabilized. Here also it is resonance destabilized. Why this shift is there? Because we have to make this back on here. Another thing you can think this is an alkene. And this is more substrate alkene. So this is more stable than this. And this is one RS. This is another RS. But this resonating structure is more stable than this. But you can also think this is 3dV clouds. Yeah exactly. Now here we have resonance now. That is also here. Alkene is getting more stability here because of more substitution. This is the logic. But you do not have any choice. Because I have to form this. So you do not have any other choice. So in this reaction would we say that the first resonance structure will form the major order? That will be a minor. Yes you can say that. Resonance is in both. Here we have how many alphyrins? One we can see in here. Over there we have one. So this gives you the major order. If this product is not given. But since we have to form this we do not have any other choice. And you have to do it. Now after this again what happens? This further you can convert into more stable carbocation. And again 1,2. So this edge comes over here. Looks good. Speed here. Okay. You will get this. Now what happens from this? H plus comes out. Right minus of H plus. So from here H plus will come out. So you will get this. Another possibility is what? We can have H plus from this carbon also. So two products are possible over here. One is the double bond. And this one. What was this? Dehydration. As a catalyst. So this has no heat. Then only H2O goes out. Okay. So since we are a catalyst. So you won't get consumed in the reaction. First step is H plus consumed. Last step it has to come out. That is the concentration of acid will be constant. What about the second one? No. See that. Prod is given. So this way only the first product comes out. But after this number of products they ask you. This will be this in this possible. Okay. So when you draw RS. You must take care of one thing. That all RS must have equal charge. Right. You all have drawn. Here it is positive. And then here the resonance structure draws out. And there is no charge involved. Right. So it is not possible. All resonating structures will have equal charge. Right. Okay fine. So you have a third structure also. Possible in this side. I think this one will be same. No problem. So they won't be same. Double bond will be more far off. Yes. That is also possible. But that will be the least amount. Because that is also resonance. So even that one is also resonance. Yes. That is also very nice.