 Hello and welcome to the session. In this session, we will discuss the following question that says, show that log of 1 plus 2 plus 3 is equal to log 1 plus log 2 plus log 3. Before we move on to the solution, let's discuss the law of logarithm in which we have log of x1, x2 to the base a is equal to log x1 to the base a plus log x2 to the base a, where this a is a positive number which is not equal to 1. x1 is a positive number and x2 is also a positive number. This is the key idea that we use for this question. Let's proceed with the solution now. We are supposed to show that log of 1 plus 2 plus 3 is equal to log 1 plus log 2 plus log 3. Now let's consider log of 1 plus 2 plus 3, this is equal to log of 6 and we can write the 6 as 1 into 2 into 3. Now using this key idea where we have log of a product to any base is equal to some of the logs of the factors to the same base. So using this we get this is equal to log of 1 plus log of 2 plus log of 3. That is we have log of 1 plus 2 plus 3 is equal to log 1 plus log 2 plus log 3 and this is what we were supposed to prove. Hence proved this completes the session. Hope you have understood the solution of this question.