 Hello and welcome to the session. In this session we discussed the following question which says solve 2 upon 3 into 5x minus 1 whole minus 2x minus 1 plus x upon 3 whole is equal to x upon 3 plus 4 upon 3. Let's proceed with the solution now. The equation given to us is 2 upon 3 into 5x minus 1 whole minus 2x minus 1 plus x upon 3 whole is equal to x upon 3 plus 4 upon 3. This is a linear equation in variable x and we need to find the value for x for this equation. To start with first we will open the brackets. So here we have 2 upon 3 into 5x which is 10x upon 3 minus 2 upon 3 into 1 that is 2 upon 3 minus 2x plus 1 plus x upon 3 is equal to x upon 3 plus 4 upon 3. Now we can write this term 1 plus x upon 3 as 1 upon 3 plus x upon 3. So this further gives us 10x upon 3 minus 2 upon 3 minus 2x plus 1 upon 3 plus x upon 3 is equal to x upon 3 plus 4 upon 3. Now we will take all the terms containing x on one side and all the constant terms on the other side. So we transpose all the x terms from the right hand side to the left hand side that is we have just 1x term x upon 3 we transpose this to the left hand side and we transpose all the constant terms from the left hand side to the right hand side. So we get 10x upon 3 minus 2x plus x upon 3 minus x upon 3 is equal to 4 upon 3 plus 2 upon 3 minus 1 upon 3. Now here x upon 3 and minus x upon 3 gets cancelled and we have 10x upon 3 minus 2x is equal to 4 upon 3 plus 2 upon 3 minus 1 upon 3. Now from here we have 3 in the denominator 3 1 times is 3 so 10x into 1 is 10x minus 3 into 2x 6x is equal to here also 3 in the denominator 3 1 times is 3 1 into 4 is 4 plus 3 1 times is 3 and 2 into 1 is 2 minus 3 1 times is 3 and 1 into 1 is 1. So from here we get 4x upon 3 is equal to 5 upon 3. Now this 3 and 3 gets cancelled and we have x is equal to 5 upon 4. So our final answer is x equal to 5 upon 4. This completes the session hope you have understood the solution for this question.