 Hello and welcome to the session. In this session, we will discuss a question which says that two dice are rolled at the same time. What is the probability that the sum of the two numbers appearing on the top of the dice is 10? Now before starting the solution of this question, we should know the result. And that is probability of an event E that is P e is equal to number of outcomes favourable to E 1 upon the number of possible outcomes. Now this result will work out as a key idea for solving out this question. And now we will start with the solution. Now it is given that two dice are rolled at the same time. Now in an experiment of rolling two dice at the same time, the total number of possible outcomes that are all these outcomes. So these are all the possible outcomes of this experiment in which the first number in each order pair is the number appearing on the first dice and the second number in each order pair is the number appearing on the second die. Now we have to find the probability that the sum of the two numbers appearing on the top of the dice is 10. Now let the event of getting on the top of the dice then number of outcomes favourable to E. Now for finding out this, we have to check the sum of the numbers in each order pair is coming out to be 10. Then that are the number of outcomes favourable to E. So after checking this, the sum of is also 10 and the sum of is also 10. So we are getting the number of outcomes favourable to E are and that is the order pair 46. So that are the order pair 6446 which is given in the key idea. Now the probability of the event E that is equal to probability of getting a sum of 10 on the top of the dice is equal to number of favourable outcomes to E over total number of possible outcomes. Now the total number of possible outcomes are 36 and the number of outcomes favourable to E are so putting this value here this will be equal to 3 by 36. Now here 3 into 12 is 36 so this will be equal to 1 by 12 is equal to 1 by 12. That's all for this session. Hope you all have enjoyed the session.