 Hello and welcome to the session. My name is Asha and I shall be helping you with the following question that says In each of the exercise 1 to 9, find the coordinates of the pokai, the vertices, the length of major exercise, the length of minor exercise, the eccentricity and the length of latest rectum of the ellipse. The first ellipse is something about the ellipse. Suppose this is an ellipse and an ellipse is essentially all the points in the plane, the sum of both distances from the two fixed points in the plane's constant. So here the ellipse shown has its major axis along the y-axis. The parameters of the ellipse are also shown in this figure. The f1 and f2 are the two pokai. Line av is the major axis and line 3d is the minor axis. Point a and b are the two vertices. Here a is the length of semi-major axis. This point denotes 0a and this point denotes 0-a. Therefore 2a is equal to the length of major axis. Here b denotes the length of minor axis. Therefore 2b gets the minor axis. a is equal to the distance of focus from the center and c is equal to root over a square minus b square. Now the standard point of the ellipse whose major axis is along the y-axis is given by x square upon b square plus y square upon a square is equal to 1. This is the standard form of the ellipse whose major axis is along the y-axis. And the vertices of this ellipse are given by 0, plus minus a. And the pokai f1 and f2 are given by 0, plus minus a. And the sensitivity, this is denoted by small e, is equal to c upon a. And the length of later spectrum is equal to 2 times of b square upon a. With the help of these few formulas we are going to solve the above problem so this is our key idea. Let's now start with the solution. Here we are given the equation of a ellipse x square upon 4 plus y square upon 25 is equal to 1. Or it can be written as x square upon 2 square plus y square upon 5 square is equal to 1. Now here the denominator of y square upon 25 is greater than the denominator of x square upon 4. Thus the major axis is along the y-axis. And as you know the standard equation for a ellipse whose major axis is along the y-axis is x square upon b square plus y square upon a square is equal to 1. Therefore on comparing the given equation with the standard equation we find here that a is equal to 5 and b is equal to 2. Now let us find c which is given by root over a square minus a square by the key idea that is 25 minus 4 which is equal to root over 21. The 4 chi is given by 0 comma plus minus c which is equal to 0 comma plus minus root over 21. The gorgeous number plus ellipse are given by 0 comma plus minus a that is 0 comma plus minus 5 length of major axis is equal to 2 into a that is 2 into 5 which is equal to 10. And the length of minor axis is given by 2 into b that is 2 into 2 which is equal to 4. Also we have to find the eccentricity denoted by a and is given by 3 upon a which is equal to root over 21 upon 5 and length of major spectrum is equal to 2 b square upon a that is 2 into 2 square upon 5 which is equal to 8 upon 5. Hence our answer is the 4 chi of the given ellipse 0 comma plus minus root over 21. Its worth is a given by 0 comma plus minus 5 length of its major axis is equal to 10 length of its minor axis is equal to 4 its eccentricity is root over 21 upon 5 and the length of the latest spectrum is equal to 8 upon 5. So that from this presentation hope you understood it well take care and have a good day.