 these conditions are given x equal to 0, when x equal to 0 velocity is 2 meter per second you need to find velocity when x equal to 5 meters. Okay, someone got the answer. Okay, whenever you see expression changing on one side they can put one paragraph one so what you should do? So, can you multiply and divide by x? So, when you do the transform into two variables. So, here what you like to get? v square by 2 minus 2 square by 2 equals to 5 cube by 3. This is not like that or not? No. What you can do? How this came? What is the velocity? Okay, a few questions on your own you cannot understand everything just by certain integration. Okay, so if I solve it, the variable is going down. So, most of the learning questions, for example, one question is a2. The same between them is d, u1 plus u2. Yes or no? So, access for both the objects to me that I use s equal to ut plus half a t square. So, d is equal to u1 plus u2 times t plus 1 plus a2 into t square. Same question if you try to solve at the relative motion clear. Okay. How simply you can get the answer? c is the velocity towards a and a is the velocity u and every time the object next to it. So, suppose c goes this way. So, of these, now you cannot at the time it takes for all the points to meet. Yes or no? That is hit number one. Just consider two points. Assume p is the observer. Who is the observer? If your c is the observer, c will be zero. And how? My time also. So, distance is the time, distance, constant speed for the distance. If you know the speed of the markers, please solve this all of you 2.5 milliseconds like this. Okay. Some, something crazy is this body's weight. From here. 4 megabit per second. So, 2 seconds for that society we answer. Speed into time, distance. It does not matter whether it is doing back and forth. I could have made, it spends 2 seconds there then comes.