 Let's now begin with the solution, we will first arrange the given data in ascending order. Now the given data in ascending order is 36, 42, 45, 46, 46, 49, 51, 53, 60, 72. Now n is equal to 10 and 10 is even. So median is equal to 2 of observation plus 10 by 2 plus 1 of observation divided by 2. This is equal to fifth observation plus sixth observation divided by 2. Now the fifth observation is 46 and sixth observation is 49. So we have 46 plus 49 by 2 and this is equal to 95 by 2 and this is equal to 47.5. Now let a is equal to median of the given data that is 47.5. We will calculate deviation of each xi from a. Now the first observation is 36 and a is equal to 47.5. So we have 36 minus 47.5 and this is equal to minus 11.5. Second observation is 42 so we have 42 minus 47.5 and this is equal to minus 5.5. For in the same pattern we have calculated deviation of other xi's also. Absolute value of each deviation. Now the first deviation is minus 11.5. Absolute value of minus 11.5 is 11.5. Absolute value of minus 5.5 is 5.5. Absolute value of minus 2.5 is 2.5. Absolute value of minus 1.5 is 1.5. Absolute value of 3.5, 5.5, 12.5 and 24.5 is 3.5, 5.5, 12.5 and 24.5. Calculate mean deviation about median. Now this is equal to 1 by n into summation i goes from 1 to 10 mod xi minus m where m is the median of the given data. Now this is equal to 1 by 10 into 11.5 plus 5.5 plus 2.5 plus 1.5 plus 1.5 plus 1.5 plus 3.5 plus 5.5 plus 12.5 plus 24.5 and this is equal to 1 by 10 into 70 and this is equal to 7. Hence the required mean deviation about median is 7. This is our required answer. So this completes the session i and take care.