 Hello and welcome to the session. Let us understand the following question today. A ladder 10 meter long reaches a window 8 meter above the ground. Find the distance of the foot of the ladder from the base of the wall. Now let us draw the figure first. Here AB is the ladder which is 10 meter long and window from the ground is 8 meter. We have to find AC. So now by Pythagoras theorem we can say that AB square is equal to AC square plus BC square. AB is 10, so we write here 10 square is equal to AC. AC is unknown plus BC is 8 square. So it implies AC square is equal to 10 square minus 8 square. Which implies AC square is equal to 100 minus 64. Which implies AC square is equal to 36. Which implies AC is equal to 6. Hence, distance of the foot of the ladder from the base of the wall is 6 meter. I hope you understood the question. Bye and have a nice day.