 Yeah, I know, right. So let's do this problem. It says name the pictured alkane, okay? So this is just an acyclic alkane. So when we're doing these acyclic alkanes, what do we need to do? Look for the longest chain, right? So you were pointing out earlier, you were like, well, do I have to go with the straight chain or can I look for some other kind of branched part of the chain? And in fact, yeah, you're going to look for whichever one is the longest continuous chain, okay? So we're going to count 1, 2, 3, 4, 5, 6, 7. So there's 7 there. 1, 2, 3, 4, 5, 6, 7, 8. There, right? Or if you did this one, 1, 2, 3, 4, 7, 8, either way, okay? So 8 is bigger than 7, right? So this is going to be called an octane, okay? So let's write that down, that part of the octane. So hopefully you can see there's two substituents of the longest chain, right? One of them's here off this third carbon and the other one's here off this fourth carbon there, okay? So they're both 1, 2, carbon units, right? So 2 carbon units. So remember, a 2 carbon unit is called a what type of group? A 2 carbon unit. Apple group, right? Yeah, an apple group. So we've got an apple coming off the 3 and an apple coming off the 4. So there's two apples. So this is a what? What, how do we name that? Dye. Dye, apple. Or dye, apple. We've got to put that dye in front of there, okay? So since it's coming off the 3 and 4 carbon, we'll say 3, 4. Dye, apple. Dye, apple. And that's the name of this molecule. Now remember, if you accidentally labeled this from the wrong way, right? Same, 4, 5, 6, 7, 8, you see that the apple groups are coming off 5 and 6 now, right? Remember, we want the smallest numbers here. So 3 and 4 are smaller than 5 and 6. So if you accidentally put 5 and 6, 5, 6, dye apple, octane, right? The other one, compare it to the other one, and that way you can see, okay, yeah, 3, 4 is bigger than, or smaller than 5, 6. So let's erase these just tonight. So are there any questions on this one? When you're naming an alkane, you will only incorporate the transincis prefixes when it is acyclic chain? Yeah, so the transincis won't apply to these acyclic alkanes because you can have free rotation around a single bond. So let's say, if we look at these two methyl groups on this molecule here, then why don't we kill this one, and we'll talk about that in a different video, okay?