 I am Shashi and I am going to help you with the following question. Question is, using elementary transformations, find the inverse of each of the matrices if it exists. The given matrix is 6-3-2-1. Let us start with the solution now. Let A is equal to matrix 6-3-2-1. Now to find the inverse by row transformation method, we will write A is equal to matrix i-A or we can write matrix 6-3-2-1 is equal to matrix 1-0-1 multiplied by matrix 1-0-1. Now we will apply a sequence of row operations simultaneously on matrix A on left hand side and the matrix i on the right hand side till we obtain the identity matrix on left hand side. Now to make this element equal to 1, we will apply row operation on R1, 1 upon 6 R1. So we can write, applying on R1 row operation 1 upon 6 R1, we get matrix 1-1 upon 2-2-1 is equal to matrix 1 upon 6-0-0-1 multiplied by A. Now to make this element equal to 0, we will apply on R2 row operation R2 plus 2 R1. So we can write, applying row operation R2 plus 2 R1, so we get matrix 1-1 upon 2-0-0 is equal to matrix 1 upon 6-0-2 upon 6-1 multiplied by A. Now since left side matrix have all 0s in the second row, so it is not possible to convert it as an identity matrix, therefore the inverse of the given matrix does not exist. So we can write, since second row of matrix on left hand side has all elements equal to 0, so the inverse of A does not exist. So inverse of the given matrix does not exist, so this is our required answer, this completes the session, hope you understood the session, take care and goodbye.