 Hi and welcome to the session. Let us discuss the following question. The question says in figure 9.27. This is the figure 9.27. A, B, C, D, E is a pentagon a line through V parallel to A, C meets D, C produced at F. Show that first part is area of A, C, B is equal to area of A, C, F. Second part is area of A, E, D, F is equal to area of A, B, C, D, E. Now begin with the solution. In first part we have to show that area of A, C, B is equal to area of A, C, F. It is given in the question that B, C, D, E is a pentagon in which a line through B that means B, F is parallel to A, C. Now since C, B is equal to area of triangle A, C, F by theorem 9.2 which states that are equal in area. Triangle A, C, B is equal to area of triangle A, C, F. So this completes the first part. Let us now move on to the second part. Second part is area of A, E, D, F is equal to area of A, B, C, D, E. Now from first part we know that area of B is equal to area of A, C, F. Let us name this equation as equation number one. Now adding D, D, C on both sides of one we get area of A, C, B plus area of A, E, D, C is equal to area of A, C, F plus area of A, E, D, C. Now A, C, B, E, D, C is equal to A, B, C, D, E. So area of A, C, B plus area of A, E, D, C is equal to area of A, B, C, D, E, D, C is equal to A, E, D, F. So area of A, C, F plus area of A, E, D, C is equal to area of A, E, D, F. We have proved that area of A, B, C, D, E is equal to area of A, E, D, F. This completes the session. Bye and take care.