 Next you write down hyper conjugation, write down it is also known as sigma pi resonance or no bond resonance, sigma pi resonance or no bond resonance, it is possible in alkene, it is possible in the case of carbocation or in case of free radical, carbonyl does not show hyper conjugation, carbonyl does not show hyper conjugation, okay, so you see the example here, suppose we have an alkene C S 3 C H double bond C H 2, okay, now you see this is the alpha carbon, alpha with respect to this functional group, right, this is double bond, we can also concept this as functional group, the adjacent carbon of this carbon is the alpha carbon we can say, right, now this alpha carbon is what, S P 3 hybridized and it has three alpha hydrogen, yes or no, number of hydrogen attached at alpha carbon is known as alpha hydrogen, so how many alpha hydrogen we have here, three, so hyper conjugation depends upon the number of alpha hydrogen, more number of alpha hydrogen, more hyper conjugating structure you can draw, right, so this molecule you see, we can write this molecule as carbon hydrogen C S 2, hyper conjugating structure if you have to draw, this sigma bond comes over here and this pi electron shift onto this carbon, right and the structure we get here is H C, here we have H plus, H C H double bond single bond C H 2, it is negative charge, okay, no H plus we have to write, that is why it is no bond resonance, yes, so fine, let me finish this first, okay, so this sigma bond comes over here, pi bond shift over here, but this H plus will not go away, it will be there only, here this carbon added, this means what, either this sigma bond can come over here, this also can come over here or this also can come over here, all these three exchange will be there, this comes and then this comes, this comes, so all these sigma bond converts into pi and then again into sigma, okay, so this can go into this way and this can also come over here and this pi sigma bond goes over here, again you will get this structure, so you see that all of them are different charges, what, yes, yes, yes, so another structure of this if you draw, that would be C H, H, all these three structure possible, see because of this carbon, this carbon is slightly more electronegative than this, this drags the sigma bond towards its sides, kind of minus okay, that's why this continuous shifting is there of sigma into pi, all these structures are called hyper conjugative structure, consider here the number of hyper conjugative structure you are drawing, these three structures are possible here because of the alpha hydrogen, what is alpha hydrogen, alpha hydrogen is the hydrogen atom, hydrogen attached with, attached with alpha carbon, okay, alpha carbon is the carbon, it's the adjacent carbon of any functional group, like this is the carbon attached to double bond, so this carbon is the alpha carbon and all these hydrogen are the alpha hydrogen, right, so number of hyper conjugative structure is equal to the number of alpha hydrogen plus one, this structure also comes, number of alpha hydrogen plus one, what, this carbon is sp2 hybridized, this is sp3 hybridized, so more percentage as character, okay, so since this is, you see first here, this sigma bond converts into pi here, sigma converts into pi, that's why it is sigma pi resonance, delocalization of electron, that's why it is resonance, okay, no bond resonance, why, because H plus present over here without any bond, okay, that's why it is no bond resonance, draw this In this case we have three alpha hydrogen plus one, yeah, three alpha hydrogen plus one, three plus one, four is connected, okay, because this is not that strong actually, this effect is not that strong, okay, so and all these sigma electrons has equal tendency to form a pi bond, right, sometimes this will form and again it comes back, this forms, comes back, this forms, so it keeps on exchanging, alpha carbon is this one, see the one, alpha carbon is the carbon which is the adjacent carbon of the functional group, okay, so this carbon is the alpha carbon here, this carbon is double bond, this carbon is the alpha carbon, adjacent carbon just here, like suppose this example if you draw, right, so how many alpha carbon hydrogen are there, we have Cs3 here, Cs3 here, C hydrogen here, C hydrogen here, C hydrogen here, six alpha hydrogen, six alpha hydrogen plus one given structure, total hypo conjugating structure will be seven, but the number of alpha hydrogen is seven, okay, no, this would be alpha, adjacent of this, adjacent of this, calculate the number of alpha hydrogen, number of alpha hydrogen, number of alpha hydrogen, number of alpha hydrogen, So, what we were discussing hyper conjugation, number of alpha hydrogen tell me all these molecules. First one it is 12, how many alpha carbon we have here, all these carbons are alpha carbon else in carbon we have to see right, 4 alpha carbon and each carbon has 3 hydrogen right. So, we have 12 alpha hydrogen here, alpha hydrogen this is alpha carbon, this is alpha carbon, alpha carbon and alpha carbon and each of these carbons has 2 hydrogen, so number of alpha hydrogen is 8, how many alpha hydrogen we have here, this one alpha hydrogen so alpha carbon, so it is 10, alpha hydrogen here, this is the alpha carbon, this is the alpha carbon for this one, 2, 1, 3, 1, 4 plus 2, 6, 1 it is very simple, why alpha hydrogen is important to count, because the stability of alkene depends upon alpha hydrogen, okay. See the application part of it, the more number of hyper conjugative structure you can draw, more will be the stability of alkene, correct so and we know that number of hyper conjugative structure depends upon what, the number of alpha hydrogen, so when the molecule is given stability you have to compare, just you count number of alpha hydrogen and if alpha hydrogen is more stability of alkene will be more, correct, so next one I write down stability of alkene, alkene, double bond, hyper conjugation is possible in alkene no, alkene, carbocation and theoretical, right, so stability of alkene write down, the stability is the ideal proportional to the number of hyper conjugative structure, the number of hyper conjugative structure which is nothing but the number of alpha hydrogen, okay, I will compare the stability of these molecules, A, I will take that, it is the same logic here for resonance, see more number of structure means what, more distribution of electron, more distribution of electron means more stability, right and that is the same logic here for resonance also, two structures are given and if you compare the stability, if the number of resonating structure is more stability will be more, because more do you have to form the distribution of electron means, first one tell me, number of alpha hydrogen here, here, 3, right, more alpha hydrogen, more hyper conjugative structure, more will be the stability, so decreasing order of stability will be this, okay, in this one, number of alpha hydrogen, number of alpha hydrogen here is 8, 3, this one is more stable, here, C 2 and 1 plus 1, 3, 3 plus 2 plus 2, 7, only this part, right, well seen, yes, we do not have any alpha carbon here, so in this case, hyper conjugation is not the case, because alpha hydrogen is not present, but in the last couple of years, we know that, in this, you see, this double bond if you consider, here we have one hydrogen, but that is not sp3 hybridized, it is sp2, so we have sp3 hybridized alpha carbon, so we have 4, 5, 6, 7, wait, wait, wait, so here we do not have hyper conjugation possible, even here also hyper conjugation is not possible, but this compound is aromatic, this one is anti-aromatic, so which one is more stable? Sir, it's because we took the chain and that's it. Yes, it is, I think in all these compounds hyper conjugation are possible, because we have sp3 hybridized alpha hydrogen, but here we do not have it, but this one is anti-aromatic, so how is that? How many pi electrons? 4 pi. The aromaticity and anti-aromatic is only defined for cyclic compound, cyclic conjugate compound, side chain we would not consider, okay, what about this one? Sir, it is not 7. Do we have alpha hydrogen here? Yes. How many? Sir, is it 7? 3, sorry, 2 plus 2, 4, and here it is. Sir, you do not count the C-H3 over the 7. No, we have, oh, this. No, no, sir, it's 7. It's 7. It's 7. It's 7. Yeah. Yeah. So is it like O or 2? No, no, no, for this L, double bond, this is alpha carbon, this is alpha carbon, that is it. So that carbon is not alpha? No, it's not, the adjacent atom is oxygen, not C-H3. No, no, no. No, sir, because O is also like a function. No, we have, we are comparing the stability of alkene with respect to this we are considering. Sir, you cannot talk any other question. No, no. Hyper conjugation is we are considering, but alkene shows hyper conjugation with respect to this one. Alpha hydrogen is 4, alpha hydrogen here is what? C plus 2 plus 2. 7. Which one is more stable? No. Which one is more stable here? The second one. But the answer is this. Hyper conjugation is fine, but here we have resonance, this alkene is stabilized through resonance, right? So the stability of alkene, the order is this I effect is laced, then we have hyper conjugation and then resonance. So if the alkene is getting stabilized by resonance, that will be the more stable alkene. So hyper conjugation is? Hyper conjugation if you consider only, then this one is more stable. Because we have here hyper conjugation possible, resonance is not possible. Here we have hyper conjugation as well as resonance. Pi sigma lone pair, that's why this one is more stable because of resonance. No, no. Now in this one, hyper conjugation you can, we can talk about, but this one is resonance stabilized also. Pi sigma pi, here we do not have resonance, no conjugation, first one is more stable. But there is only for alkene. Only for alkene. But what is only for alkene? No, no, no. It is overall order. Whatever intermediates we have, cartocatile, carbonyl, theoretical, resonance always dominates hyper conjugation and I effect. This one? For this double bond, we have two SP3-hybrid alkyl. And for this double bond, we have two SP3-hybrid alkyl. But it is SP2. This is also SP2. For this one, this is also SP2. You won't count this. Because we require SP3-hybrid alkyl, not SP2. So two plus two total four alpha-hybrid alkyl. For this one, it will be two plus two, two plus four. Okay? Understood? So now in the molecule, if you have only hyper conjugation possible, then we will count what? If only hyper conjugation is possible, then we count alpha-hyrogen and we can compare separately. What happens if number of alpha-hyrogens is same, like in this molecule? Counts, resonance, or you can count it. This three. You have to compare the stability of these three molecules. See, when number of alpha-hyrogens is same, the number of alpha-hyrogens is what? Six. Number of alpha-hyrogens? Six. Number of alpha-hyrogens? Six. So when the number of alpha-hyrogens is same, then what we do you see? The first compound is this. So what's the difference between the second and the third? This one is cis and this one is trans. Cis-trans, we will discuss that in isomeric. Okay? So it's a different molecule. Both are different. However, the molecule formula is same. It is also buttuine. It is also buttuine. But the name of this compound is cis-buttuine. This is trans-buttuine. What is cis-trans? We'll discuss that in isomeric. Cis-trans. Okay? Yes. EZ we have, syn-antib we have. We'll discuss that in isomeric. Okay? This molecule is the CH2H double bond CH2. Okay? So why did I do like that? CH2, sorry, H2C double bond. I'll give you an understanding. Hyper-conjugative structure you have to draw. This sigma bond comes over here. And this pi electron goes over to this carbon. Okay? So we get what? CH2H plus double bond C single bond CH2 negative. Correct? Right? It's the same thing. Alpha hydrogen here we have, alpha carbon. Sigma converts into pi. Pi converts into sigma. Hyper-conjugative structure. This C double bond C alpha carbon, right? It is the same thing I have written this way. CH3CH double bond CH2. The first example that we have done. In this one, this hydrogen is not there. Instead, we have one more CH2. That is the only difference. Okay? So this H2 and this H, it comes over here. And this also. Hyper-conjugative structure. Okay? So you will get this. Now this is a carbon ion we are getting. And this is what? One degree carbon ion? Yes? One degree carbon ion. So we have to compare the stability of this carbon ion in these three molecules. Okay? If you have equal number of alpha hydrogen, then we will compare the stability of intermediate, which is carbon ion in this case. Okay? Even if you draw the hyper-conjugative structure with all other five hydrogen, you will get one degree carbon ion only. Is it? Okay. With all these three plus two five hydrogen, you will get this structure only. One degree carbon ion. Now, the other one you see this one. CH2H. CH double bond CH. CH3. So you get here what? This comes over here. And this comes over here. So you get CH2H plus double bond CH. Single bond CH. Negative CH3. Okay? This is what? This is two degree carbon ion? Okay. Two degree carbon ion. We will follow this two hydrogen and this one three hydrogen. Again you will get two degree carbon ion also. The higher the degree the more stable one. For carbon ion that is different. Decreases as degree increases. Yeah. Carbon, cation. Higher degree more stable. Because of plus sign. Okay. Okay. Now, so here we are getting two degree carbon ion. Here what we get? This one CH2. Okay. Again we are getting here. So which one is more stable? Two degree or one degree? One degree. One degree. One degree is more stable. So obviously we can say this one is the most rank of this one. This will be first. Second and third we have a confusion. Right? Because both gives two degree carbon. Now in this what we do? When the methyl group present on the same side. Okay? Less. The hindrance is comparatively more here. Trans, when the methyl group are opposite side the distance is more here. And hence the hindrance is less. Hindrance is less, stability is more. Right? So this is first. The trans one is second and the cis. Modern stability. Okay. So basically the number of alpha hydrogen is more. Then we will compare the stability with respect to the stability of the intermediate which is a carbon ion in case of hyper conjugation in alkane. How is this more than what is given in trans? Cis is generally if you draw this structure CH double bond CH. CS3 and CS3. One molecule is this. So this is trans compound because the both methyl group present on the opposite side. Okay? Only one thing you understand here in the trans the distance is more between the two methyl group. Cis what happens? The distance between the methyl group is comparatively less. Both methyl group present on the same side in this way which is the third molecule. This distance is lesser than this. That's why the repulsion here is less. Here the repulsion is more and hence this one is less stable. Generally cis alkene is less stable than the trans. Okay? That's why this is more stable than this. Okay? One thing also we can conclude here. You see this carbon and this carbon, the double bonded carbon atom. Here the branch on the double bonded carbon atom is two. Here the branch is what? One. One. Here also it is one. So when the branch on the double bonded carbon atom increases, the stability of alkene increases due to hyper conjugation. That also we can. More branch here, this one is more stable out of the three. Right? And here the branch on the double bonded carbon atom is two. So as the branch on the double bonded carbon atom increases, the stability of alkene increases due to hyper conjugation, not overall. The stability due to hyper conjugation increases. Okay? So hyper conjugation is less stable. Which one? The middle one is less than, sorry, more than the third one. Yeah. Okay? So that branches thing will also work with the other two categories we gave. Like free radices and catamels. For carbon atom it depends, it depends on the molecule. You see the example, it depends. But alkene due to hyper conjugation is this one. Always.