 Hello and welcome to the session. In exercise 1 to 8, find the equation of the line that satisfies the given condition. Sixth one is intersecting the y-axis at a distance of two units above the origin and making an angle of 30 degree with the positive direction of x-axis. First let us learn how do we find the equation of a line which passes through a given point. Let the point be x1, y1 and let the slope of the line be m. Then the equation of line as given by y-y1 is equal to m times of x-x1 where xy is in general point on the line. So with the help of this idea we are going to solve the above problem. So this is our key idea. Fine. Now so let's start with the solution. Now here we are given that the line intersects the y-axis at a distance of two units above the origin. So this is one unit and this is two units. Now the name of this point is 0, 2 that is here the x coordinate is 0 and the y coordinate is 2. So the given point is 0, 2 and the slope that is denoted by m is given by tangent of theta where theta is the angle made by the line with the positive direction of x-axis and that is 30 degrees. So we have 10, 30 degrees this is equal to 1 upon root 3. So the slope of the line is 1 upon root 3 and here the given points are 0, 2 so this implies x1 is equal to 0 and y1 is equal to 2. Therefore the equation of the line is equal to y-2 is equal to m times of x-0, y-2 is equal to 1 upon root 3 into x, root 3 y-2 root 3 is equal to x or x-root 3 y plus 2 root 3 is equal to 0. Thus equation of a line satisfying the given condition is given by x-root 3 y plus 2 root 3 is equal to 0. So this is our answer and this completes the session. Take care and have a good day.