 Hello and welcome to the session. In this session we discussed the following question that says replace the letters of the English alphabet by digits. Two or more letters may have the same value to complete the procedure of division. We are given this procedure of division. Now let's move on to the solution. This is the procedure of division given to us. We need to replace all these English alphabet letters by some digits and two or more letters may have the same value. Now you can see that in the questions we have one here and here we have 28 and we know that 28 multiplied by 1 is equal to 28. So this would mean that here in this divisor we have 28 that is we have AB is equal to 28 or you can say A is equal to 2, B is equal to 8. We write 28 here that is 28 multiplied by 1 gives us 28. As we get A equal to 2 and B equal to 8. Now next in place of C we should have some number such that its difference with 8 gives us 5. We know that 13 minus 8 is equal to 5. So in place of C we should have 3. Now this 1 would be subtracted from this 4. This gives us 3 and now we subtract this 2 from 3 which gives us 1. So in place of H we would have 1. So now we have got the values for C and H also. C is 3, H is 1. Now we have got the remainder as 15 and we take down the next digit. We already have the 6 written here. So obviously in the dividend the next digit would be 6 that is in place of D we can write 6. So we have got the value for D as 6. Now we divide 156 by this divisor 28 and we have 28. 5 times is 140 and the remainder is 16 here. So in the question we would write 5 here in place of F. We write 5 that is we get the value of F. So in the question we have F as 5 and we write 114 in place of ijk that is we have i is equal to 1, j is equal to 4 and k is equal to 0. Now 156 minus 140 gives us 16. So in place of lm we can write 16 that is we now have l is equal to 1, m is equal to 6, m is equal to 1, m is equal to 6. We know that 28 6 times is 168 and you can see we are getting the remainder as 0. So obviously we would have 8 here in place of n. So in place of n we put 8 and in place of g we would have 6 because 28 6 times is 168. Thus we get g is equal to 6 and we write 8 and also n is equal to 8 and obviously this digit e would be same as 8. So in place of e we write 8 that is the value of e is 8. Now obviously pqr would be 168 since its remainder is 0. So we write here 168 that is we get 168. p is equal to 1, q is equal to 6, r is equal to 8. So we have found the value for all the English alphabets used in this process of division. So this completes the session. Hope you have understood the solution for this question.