 Hi and welcome to the session. I am Shashi and I am going to help you to solve the following question. Question is, choose the correct choice in the following and justify it. First part is, third year count of the AP 1074 is A97B77C-77B-87. We have to choose the correct answer. First of all, let us understand that the nth term of an AP with first term A and the common difference D is given by An is equal to A plus n minus 1 multiplied by D. This is the key idea to solve the given question. Let us now start with the solution. We are given AP 74. Here we can see the first term is equal to 10. So we can write A is equal to 10 and the common difference D is equal to 7 minus 10 equal to minus 3. D is the difference between the constitutive terms of the AP. Now we know by key idea, nth term of an AP is given by A plus n minus 1 multiplied by D where A is the first term and D is the common difference. Now we have to find the 30th term of the AP. So we can write 30th term of the AP is equal to 10 plus 30 minus 1 multiplied by minus 3. We have A is equal to 10, D is equal to minus 3 and n is equal to 30. So we have substituted the corresponding values of A, n and D in this expression. So we get 30th term is equal to 10 plus 29 multiplied by minus 3. Now this implies 30th term is equal to 10 minus 87. This further implies 30th term is equal to minus 77. So the 30th term is minus 77. So C is the correct answer. So we can write C is the, this completes the session. Hope you understood the session. Take care and goodbye.