 Hi and welcome to the session. I'm Kanika and I'm going to help you to solve the following question. The question says what length of tarpulin 3 meters wide will be required to make conical tent of height 8 meters and waist radius 6 meters. Assume that the extra length of material that will be required for stritting margins and waisted in cutting is approximately 20 centimeters. Use pi is equal to 3.14. Let's now begin with the solution. We will first find curve surface area of the cone. We know that curve surface area of cone is equal to pi rl. Now here we are given that r is equal to 6 meters and h is equal to 8 meters. Let's first find l. l is equal to square root of h square plus r square. Substitute the value of h and r. So this is equal to 8 square plus 6 square meter and this is equal to square root of 100 meter and this is equal to 10 meters. Now substitute the value of pi r and l in this. Pi is equal to 3.14. r is equal to 6 meters and h is equal to, sorry, l is equal to 10 meters. So this is equal to 188.4 meters square. Now we will find length of tarpulin, tarpulin required is equal to area of tarpulin required divided by width of tarpulin. Now area of tarpulin required is equal to curve surface area of the cone that is 188.4 meters square and we are given that width of the tarpulin is 3 meters. So this is equal to 62.8 meters. We have also given that extra material required for stritting margins and cutting is equal to 20 centimeters and this is equal to 0.2 meters. So total length of tarpulin required is equal to length of the tarpulin that is 62.8 meters plus extra material required for stritting margins and cutting that is 0.2 and this is equal to 63 meters hence are required answer is 63 meters. So this comes to the session I and take care.