 Hi, and welcome to the session. I am Deepika here. Let's discuss the question. Find the approximate value of f of 2.01 where fx is equal to 4x square plus 5x plus 2. Let's start the solution. Given fx is equal to 4x square plus 5x plus 2, therefore, f dash x that is equal to dy by dx is equal to 8x plus 5, like x is equal to 2 and delta x is equal to 0.01. Now f of x plus delta x is equal to 4 into x plus delta x whole square plus 5 into x plus delta x plus 2 and delta y which is a small increment in y corresponding to the increment in x is equal to f of x plus delta x minus fx. This implies f of x plus delta x is equal to f of x plus delta y. Now this is equal to f of x is 4x square plus 5x plus 2 plus dy by dx into delta x. Now this is equal to 4x square plus 5x plus 2 plus dy by dx is 8x plus 5 into delta x is 0.01. Now this is again equal to therefore f of 2.01 is equal to 4 into 2 square plus 5 into 2 plus 2 plus 8 into 2 plus 5 into 0.01 and this is equal to 4 into 2 square is 16 plus 10 plus 2 plus 21 into 0.01 and this is equal to 28 plus 0.21 Hence 2.01 is equal to 28.21 And the answer for the above question is that is the approximate value of f of 2.01 is 28.21 and this is our answer. I Hope the question is clear to you. Bye and take care