 Hi and welcome to our session. Let us discuss the following question. The question says, in each of the exercises having to 12, find the equation of the parabola that satisfies the given conditions. Given conditions are vertex at 0, 0 and coordinates of focus at 3, 0. Before solving this question, we should know that if the parabola has vertex at the origin focus at point a, 0 and direct fixed, x equals to minus a, then the equation of parabola is of the palm y square equals to 4ax. This is one of the standard equations of parabola. Now, given this in one, let us now begin the distribution. Now clearly, the coordinates of the focus that is 3, 0 lies on the positive side of x-axis. The axis of the axis of the parabola and this parabola opens to the right, like in this video. Now, we have learned that if the parabola has vertex at the origin, focus at the point a, 0 and direct fixed, x equals to minus a, then equation of parabola is of the palm y square equals to 4ax. Now here, since the focus of required parabola in the form of a, 0, its vertex is at the origin, required equation parabola is of the palm y square equals to 4ax. Now here, we are given that a is equal to 3, so on putting a as 3 in this equation, we get y square equals to 4 into 3 into x. This implies y square equals to 12x. Hence, a required equation of parabola is y square equals to 12x. This completes the session. Bye and take care.