 Hello everyone, this is Shila Ratna Bansode from Walshan Institute of Technology, Solapur. Today we are going to see the topic section of solids and in that particularly we will be dealing with the solid type prism. Let us move further, the learning outcomes. At the end of this session, students will be able to draw the sectional view of prism. As we all know, prism is a kind of solid which has a base and a top parallel to each other. We can have a square prism, a hexagonal prism, a pentagonal prism or a triangular prism. So we can say that the prism has faces as well as edges. Let us move further, an example, a hexagonal prism, 35mm side and axis 70mm long is resting on one of its base edges on the ground, that is HP, such that the axis is inclined at 30 degrees to HP and parallel to VP. It is cut by an inclined plane at an angle of 45 degrees to HP and perpendicular to VP. The same cutting plane passes at a distance of 25mm above the base along the axis and for this case, we have to draw the front view and the sectional top view. Now analyzing the question, we can say that or from this condition that the prism is resting on one of its base edges on the ground, from this condition we can say that the prism is resting on its base on HP that is horizontal plane or the ground in the first stage. As this problem being of two stages, in the second stage, we will obtain the desired sectional front view and sorry, the desired sectional top view and front view. So in the first case, we need to draw the hexagonal prism resting on HP. Further, it is cut by inclined plane, which is inclined at 45 degrees to HP. Inclination with HP is seen in front view and the cutting plane is also perpendicular to VP, hence the cutting plane will be seen as a line view in front view. One more condition for the prism is that the prism has its base edge in contact with HP such that the axis of the prism makes an angle of 30 degrees to HP. So this shows the second condition of the prism or the final condition of the prism where we need to cut the prism by this given plane, which is 45 degrees inclined to HP. Let us move further to draw the given prism. First the XY line or the reference line. Now as the prism is resting on HP, we will start with front sorry top view where we will draw a hexagon. The position of the hexagon is the two edges are perpendicular to XY. This hexagon of 35 mm side we will name it before that we will project this all the corners in vertically upward direction, so that we can complete the hexagon in front view. As you can see at the middle you get an edge, so we have darkened this line. This is height 70 mm. This is the naming. We have named it as 1, 2, 3, 4 in this fashion and corresponding naming in the front view as 1 dash 2 dash 3 dash 6 dash and 4 dash 5 dash. Now this is the first or the initial condition. Now moving further for second condition, the second condition is this prism will be inclined at an angle of 30 degrees to HP. So we have to redraw the front view with an inclination of 30 degrees to HP, but the condition is that the edge 4 phi the edge 4 phi will be in contact with XY. So let us draw this or let us redraw the front view at an given inclination. So you can see that the edge 4 phi is in contact with XY and the axis is inclined at 30 degrees to HP, we will complete the naming. So this is the required position of the prism as for the given condition. Now moving towards the cutting plane. So this is the cutting plane as the cutting plane is perpendicular to VP, it is seen as a line view plus it is inclined at an angle of 45 degrees to HP and 25 mm from base. 25 mm distance will be measured on this edge 3 dash 6 dash. Now let us complete the top view. Complete the points, before that we have darken the remaining part of the prism, now projecting the points, point 1 dash 2 dash will be projected from front view and corresponding point 1 and 2 will be projected from the previous top view. Now we will be projecting the points 3 dash 6 dash and 4 dash 5 dash, we get the required base of the prism which is named as 1 2 3 4 5 6. So this is the required base, we will join this. So this is the part which stays after cutting the prism moving further. Now here on screen you can see that we have obtained the points P1, P2, P3, P4 and so on. These are the points from this cutting plane. So wherever the cutting plane shown in red cuts the edges, we have named those points as P. So cutting plane cutting the edge 1 dash 2 dash will be named as P1, P2. Here P3, P4 or P3, P6 and here 4 and 5. Now point 1 dash, point P1, P2 will be projected on the side 1 and side 2. So we will get the point P1 and P2. So point P3, P4, P5 and P6 will be obtained by projecting those points on the corresponding sides in the top view. So this is the required sectional view of the other section that is being obtained after by cutting the plane, cutting the prism in the required fashion. We will dark the remaining portion of the prism. So this part of the prism stays after being cut. The inner sides will be in dotted form as they are hidden and we will draw the section lines at the cutting part. So this is the complete projection of the prism that is hexagonal prism when it is cut by an angle of 45 degrees the cutting plane makes and when the prism makes an angle of 30 degrees with HP. Thank you.