 Hello and welcome to the session. In this session we discuss the following question which says construct a quadrilateral PQRS in which PQ is equal to 2.9 centimeters, QR is equal to 3.2 centimeters, RS is equal to 2.7 centimeters, SP is equal to 3.4 centimeters and angle P is equal to 70 degrees. Now let's move on to the solution. First we will draw a rough sketch of the quadrilateral PQRS. This is the rough sketch of the quadrilateral PQRS where we have PQ is 2.9 centimeters, QR is 3.2 centimeters, RS is 2.7 centimeters, SP is 3.4 centimeters and angle P is 70 degrees. Now we will construct this quadrilateral step by step. First we will draw PQ equal to 2.9 centimeters. So this is the line segment PQ of measure 2.9 centimeters. Now in the rough sketch of the quadrilateral PQRS you can see the angle P is of measure 70 degrees. So in the next step we make angle XPQ equal to 70 degrees. So this angle XPQ is of measure 70 degrees. Now PS is 3.4 centimeters. So in the next step we say that with P as the center and radius 3.4 centimeters draw an arc on the ray PX. So this is the arc of radius 3.4 centimeters with taking P as the center and let this point be S. So we have PS is equal to 3.4 centimeters. Now next step would be to locate the point R for this. First we will take with Q as the center and radius 3.2 centimeters draw an arc. So we have drawn this arc with Q as the center and radius 3.2 centimeters. Then in the next step we take S as the center and radius 2.7 centimeters draw an arc cutting the previous arc. So this arc is drawn with S as the center and radius 2.7 centimeters. It is intersecting the previous arc and we take this point of intersection of the two arcs as the point R. Then in the next step we join RS. So now we have joined RS and RQ. This RQ is of measure 3.2 centimeters. RS is of measure 2.7 centimeters. So now we say that PQ RS is the required quadrilateral. This completes the session. Hope you have understood the solution for this question.