 Hello and welcome to the session. Let us understand the following question today. ABC is an equilateral triangle of site 2A, find each of its attitudes. Now, before starting with the solution, let us draw an equilateral triangle ABC of site 2A units where AD is perpendicular to BC. Here is a triangle ABC with each of its sides as 2A and AD is perpendicular to BC. Now, AD is perpendicular to BC, then D is the midpoint of BC. Therefore, CD is equal to half of BC. We can write CD in terms of BC and BC is given to us as 2A. So, CD is equal to half multiplied by 2A. Now, 2 and 2 gets cancelled, so it is equal to A. That is, CD is equal to A. Since triangle ADC is a right triangle right-angled at D. Therefore, by Pythagoras theorem, we can write AC square is equal to AD square plus CD square. AC is given to us as 2A, so we can write 2A. The whole square is equal to AD square plus CD we have found it is A, so plus A square. Now, it is equal to 4A square is equal to AD square plus A square. Therefore, AD square is equal to 4A square minus A square. Therefore, AD square is equal to 3A square AD is equal to under root 3A. Hence, each of altitude is equal to A root 3. Therefore, required answer is A root 3. I hope you understood the question. Bye and have a nice day.