 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that find the centre C radius and equation in standard form of the given circle. We know that standard equation of the circle with radius r and centre having coordinates hk is given by x-h whole square plus y-k whole square is equal to r square. With this k idea let us proceed to the solution. In this question we are given a circle. First of all let us find the coordinates of its centre C. Now from this graph we can see that at the point C x-coordinate is minus 2 and y-coordinate is 2. So coordinates of centre C are given by the ordered pair minus 2 to 2. Now let us find its radius. In this graph each square box is equal to 1 unit and we know that distance of any point on the circle to its centre is radius of the circle. So here from this point that is we name this point as point A to point C which is the centre of the circle we have 2 square boxes which means 2 units. So here radius r of the circle is equal to 2 units. Now we shall write the equation of the circle where centre is given by the ordered pair minus 2 to 2. So here we have the value of hs minus 2 and the value of k as 2. Also radius is given by 2 units so r is equal to 2. From the key idea we know that standard equation of the circle with radius r and centre having coordinates hk is given by x minus h whole square plus y minus k whole square is equal to r square. Thus we put h is equal to minus 2, k is equal to 2 and r is equal to 2 in this equation and we get x minus of minus 2 whole square plus y minus 2 whole square is equal to 2 square which implies that x plus 2 whole square plus y minus 2 whole square is equal to 4 thus x plus 2 whole square plus y minus 2 whole square is equal to 4 is the required equation of the given circle in standard form with radius 2 units and centre C having coordinates minus 2 to 2. This is the required answer. This completes our session. Hope you enjoyed this session.