 In this video, we present the solution to question number two for practice exam number four for math 1210, in which case we're asked to compute the limit of as x approaches zero of e to the x minus one over x. So my temptation is that as the functions continuous, I just want to plug in x equals zero, we're going to get e to the zero minus one over zero, which e to the zero is one. So you get one minus one, which is zero. So we get zero over zero, which the fact that we get zero over zero means that I want to use L'Hopital's rule to help me out here. So I'm going to kind of erase this right here, and then try this again. So by L'Hopital's rule, if I take the derivative of the top and the bottom, right, we take the derivative e to the x minus one, we'll just give me e to the x. If you take the derivative of x, you're just going to get a one. So we take the limit as x approaches zero in this situation, we can plug in x equals zero, we get e to the zero, which is equal to one. And so by L'Hopital's rule, we see that the correct answer will be c number one.