 Hi, and how are you all? Let us discuss the following question. It says to receive grade A in a course, one must obtain an average of 90 marks or more in first in five examinations, each of 100 marks. If Sunita's marks in first four examinations are 87, 92, 94 and 95, find minimum marks that Sunita must obtain in fifth examination to get grade A in the course. So, let us first convert this word problem into a numeric inequality. Marks obtained by Sunita first four test are 87, 92, 94 and 95. Now, let the marks obtained by her in fifth examination, the test let us say as this is the word which is used B equal to X. Total marks will be equal to 87 plus 92 plus 94 plus 95 plus X which is equal to B68 plus X. Now, her average marks will be equal to 368 plus X and it should be divided by five as there are five tests. But according to the given condition, average marks should be 90 or more than that. So, it should be the marks, the average marks that we found out in the above step should be greater than equal to 90. Now, we need to solve this inequality to get the required value of X. So, on multiplying both the sides by five we have 368 plus X is greater than equal to 450. Now, on subtracting 368 from both the sides we have X is equal to or X is greater than equal to 82. So, this states that minimum marks Sunita should get to get grade A is equal to 82 or we can write it in a short form that her marks should be greater than or equal to two. So, this is a required answer. I hope you understood how to proceed on with this solution. Bye for now.