 Okay, for the last problem today, we'll do this one, a bomb-calorie-meter problem. So 5.00 grams of octane are burned in a bomb-calorie-meter, containing 200 grams of water. How much energy in calories is released if the water temperature increases 6.00 degrees Celsius? So what you've got to remember here is the heat-release equation, okay? So Q equals delta Ts times MS times SHS, okay? So this is the change in temperature of the solvent. This is the mass of the solvent, and this is the specific heat of the solvent. Okay, the specific heat isn't given in this problem, but I'll give it to you on any sort of test. So the specific heat of water is 1.00 cal for 1 degree Celsius times grams, okay? So the change T of the solvent is given at 6.00 degrees C, and the mass of the solvent is given at 200 grams, or 2.00 times 10 squared grams. So all you've got to do is calculate Q, so Q equals 6.00 degrees C times 2.00 squared grams, 1 degree C grams. We can cancel our units, degree C, grams, cancel, and we're left with calories, okay? So all we've got to do is multiply 6 times 200, and of course that equals 1.20 calories, but if we wanted to do the right amount of significant figures, that's not right, because we have 3, 3 and 3, so we're going to put it, we could change it to big C cals, but let's do that. So we've got 1,000 cal for the 1 degree C cal. So the big C cals remember are nutritional calories, okay? And that's going to equal 1.20 big C cals, or 1.20 K cals, you could write it, or you could write it, keep it in little C cals as 1.20 times 10 to the 1, 2, 3, third cal. So any of those answers, any one of those answers is correct. Thank you.