 Hi, and welcome to the session. Let us discuss the following question. The question says, integrate the following functions. Given function is e to the power 5 log x minus e to the power 4 log x upon e to the power 3 log x minus e to the power 2 log x. Let's now begin with the solution. In this question, we have to integrate the function e to the power 5 log x minus e to the power 4 log x by e to the power 3 log x minus e to the power 2 log x dx. Now, this is equal to integral of e to the power log x to the power 5 minus e to the power log x to the power 4 upon e to the power log x to the power 3 minus e to the power log x squared dx. We know that e to the power log x is equal to x. So this is equal to integral of x to the power 5 minus x to the power 4 by x to the power 3 minus x to the power 2 dx. This is equal to integral of x to the power 4 into x minus 1 by x squared into x minus 1 dx. Cancel x minus 1 from both numerator and denominator. And x to the power 4 by x squared is x squared. So now we have integral of x squared with respect to x. We know that integral of x to the power n is x to the power n plus 1 by n plus 1 plus c. Now here in place of n, we have to, so integral of x squared is x to the power 3 by 3 plus c. Hence our required answer is x cubed by 3 plus c. So this completes the session. Bye and take care.