 You can just take the snapshock, you don't need to write down, anyways, okay, please focus here. Acceleration, focus here, so that is how it looks like this. We have shown the velocity and acceleration at four points, so all the points also I can show. Now tell me, is the magnitude of velocity changing? No, magnitude of acceleration changing? No. So these two things are fixed, but the equation, you remember equations of motion, we simply u plus 80, okay, so all these equations usually track, right, but here what we should track? Direction. I just need to track where the particle is and I can find out its velocity and acceleration, because the magnitude of velocity and acceleration is fixed. So essentially I need to track at what, how much, how much is the displacement. I need to track the displacement, change in displacement and then change in velocity. But if object is going in a certain direction, we are dealing, so angle assignment is, okay, okay, which is delta theta. Change in angle, change in angle, if initial angle is 30 degrees, how much distance the particle has moved, distance. If delta theta is the angle of rotation, please write down, if delta theta is the angle of rotation, r delta theta is the distance, r delta theta is the distance, okay, fine. So d theta by d, very small displacement, that I can write in a small displacement. So if it is going in a very small angle, let's say delta theta, this length is r d theta, this length is r d theta, this is d theta, okay. So d r, there is r d theta, so this is r d theta by dt, which is what, r into omega, okay. Please write down, at any moment, it will be equal to r times omega, it will be equal to r times omega, r omega. Please write down r omega. If you know the angle velocity, you can find the speed of the particle, right. So d r is r d theta divided by dt, so d theta by dt, a is constant, is equal to u plus at, s equal to ut plus half at square, and v square equal to u square plus 2 at s, right, if a is constant. Now, this is what mathematical solution is, similar equation, like this. Instead of v, I am writing omega, instead of a, I am writing alpha, so the solution of this equation, if alpha is constant, should be what? Tell me this equation. Instead of v, what should be there? Omega. Omega, so omega is equal to initial angle velocity, very similar looking, equals to omega naught square plus 2 alpha r. Omega naught is something called, then sense can be checked by clockwise and anti-clockwise, that's all. 60 rpm. rpm is what? Revolutions per minute. You need to find out, seconds. All of you ready, but if you have not followed the step, you are not able to replicate the same way of problem solving, for the completed question. So, you must know which equation you have used. Please write down, in a uniform circle question, in a uniform acceleration is 0. In a uniform circle question, angular acceleration is 0. So, remember, if an object travels with a constant velocity, the specimen is not there. Similarly, here also, if constant and angular velocity, if this is 0, it will be simply omega. This is one revolution per second or not? In one revolution. So, if I have to do it per second, so omega is 2 pi radians per second. So, data theta is 2 pi into 10, which is?