 Okay, so this is the first mechanism and the carboxylic acid unit, of course, fairly straight forward. Well, we could put salt in here if we want to. Okay, so this is taking benzoic acid and making sodium benzoate out of it, okay. So, pretty straightforward mechanism. I'm going to erase the products. Okay, so what I would do is write that bond, of course, put your lone pairs. And then, remember, sodium hydroxide. Sodium is the spectator arm. It doesn't do anything. Hydroxide is the active ingredient in this stuff, right? Very strong base. This is a pretty strong mass that we'll get into pKa values and stuff like that in a second. So the deprotonation occurs. And you can go all the way to the other resonance form if you want. Okay? Or you could have stayed on the former resonance form. But I just did that just to show you. Because, of course, both resonance forms are the same. It's equilibrium arrow, correct? Yeah, that's going to be equilibrium arrow. But, of course, the equilibrium is going to be so far on the this side. Because this is very strong and this is very strong, you know. So it's effectively straight arrow. And A plus is going to be the counter-ion. So if you wanted to put an equilibrium, I would do something like that. Again, you don't have to write it like this. You could have written in the other resonance form, which would have been just as good. Just showing those electrons stopping there. So the mechanism to get there would have been. But either way, this thing and this thing are the same thing. They're just resonance forms of each other, okay? And, of course, in this, because it's the same range. So are there any questions about this? In fact, it's these two resonance forms that make this reaction forward. Why? Because the more resonance forms you have, the more stable you are. So which one's more stable? The carboxylate or the carboxylic acid? The carboxylate is actually more stable, okay? Because it's got the two new resonance forms over the one. Is everybody cool with that?