 To find the image of a convex spherical mirror we're going to use again our three special rays the one that is parallel that will go through the focal point The one that goes through the focal point will become parallel and the one that goes to the center is reflected as if there will be a plain mirror here. And now with the concave mirror we have figured out that that kind of behaves like a converging lens where an object left of the focal point will produce a real image and object on the right of the focal point will create a spherical image. So we expect here to get similar behavior like with diverging lens, meaning that we get a virtual image. Similar to the diverging lens the focal distance is given as a negative number, meaning that we're going to be using the focal point on the other side. Here we use the focal point on the left side to draw the rays. Here we're going to use the one on the right side. And just remember how you figure out the focal distance if you know the radius of the mirror. So the magnitude of your focal distance is to radius over 2. So let's start with our special rays. Let's start with a parallel one. So a parallel ray is spread out. It's diverging. So in my convex mirror it's kind of like a diverging lens. The parallel rays do not really meet in a focal point. They spread out. But if you backtrack time it looks like they all would have come from that one focal point. One that is in at the focal point should be parallel to the central axis. And that would be at least the one that goes to the center of my mirror. So here we'll behave as incoming angle is equal to outgoing angle. I have found as expected a virtual image.