 Next I know hyper conjugation in free radical free radical it is very simple just to see one example only one example we will do CH2H it is similar to carbocation free radical right this one electron comes on to this carbon and one goes on to this hydrogen this radical is radical combines and gives a double bond CH2H radical double bond CH3 and further we can draw two more structure for this again the number of hyper conjugative structure is equals to the number of alpha hydrogen plus the given one stability is again same like carbocation we can compare this okay this one you will get is not that important out of the alkene and carbocation is most important okay now like plus H sorry plus I minus I plus M hyper conjugation also we have two types hyper conjugation again it is plus H and minus H plus H is what electron releasing plus means electron releasing minus H means electron withdrawing or electron withdrawing may it's from the reverse hyper conjugation okay reverse hyper conjugation plus H and minus H it's only plus H minus H is possible only with chlorine only with chlorine only with chlorine and I will discuss that later just for here you write down it shows only by CCl3 that's why it is rare and not that important okay and we also call it as reverse hyper electrons now you see here in this molecule hyper conjugation possible do we have hyper conjugation possible in this and what is the condition of hyper conjugation Sb3 hybridized alpha hydrogen this double bond this carbon is Sb3 hybridized alpha hydrogen okay understood this right the condition you just have to apply double bond alpha carbon and three hydrogen Sb3 hybridized so here is hyper conjugation possible when you draw the hyper conjugation structure of this this comes over here and this final extra is different to this now it seems like we have plus M and minus M as well as structure so what we got here this ring with this bond and negative charge here C H plus H further this comes over here it is resonating the structure and this gets you all the structure you draw now you see this C H3 is what it is releasing electron C H3 is releasing electron to this ring that's why this shows plus H effect this is plus H okay positive hyper conjugation releasing electron to the ring okay now you see due to plus H effect what happens what we can say plus H effect increases electron density at density at ortho and para position ortho para I have discussed from last class because you see the negative charge is coming at ortho and para position right so hyper conjugation increases electron density at ortho para position plus H effect okay that's why any group if it is present at ortho and para position that can show hyper conjugation as well as mesomeric effect mesomeric effect we have discussed last class that when you draw the resonating structure either the electron density increases at this two position or decreases we get negative charge or positive charge at ortho or para position if it is plus M then we get negative charge if it is minus M then we get positive charge right so any group what you have to keep in mind any group present at ortho and para position can show both mesomeric and hyper conjugation both pick possibly at meta position we have only I effect at meta position since the charge is not present there so at meta position we have only I effect very important we will use this particular point question from this ortho and para position hyper conjugation possible right any group attached at ortho and para position shows mesomeric effect and hyper conjugation okay the minus H effect we have four molecules CF3, CCL3, CBR3, CIT this discussion is not that important because only one molecule shows minus H effect that is CCL3 this won't show this also won't show this one okay one thing I forgot to write here you see one thing this carbon hydrogen bond is breaking right if this bond is easier to break hyper conjugation is it possible easily when carbon hydrogen bond is easier to break hyper conjugation is possible easily right so if you have isotopes of hydrogen like CH3, CD3 and CD3 which one shows maximum hyper conjugation the one which has the weakest carbon and that isotope bond CH3 I have discussed this in I effect right I effect for CT3 is maximum but hyper conjugation of CX3 is maximum because the carbon hydrogen bond length CH bond length is what is maximum here then we have CD and then we have CD all these information you should have actually bond length so I didn't understand I only CL showed minus H effect I will come to this just this is a little bit more I forgot to do I will come back to this okay so if isotopes of hydrogen are given then CH3 shows maximum plus H why because the bond length of CH is maximum hence bondage length is minimum you can break this bond easily hyper conjugation is now CCN3 why only CCN3 shows minus H effect and we also call it as reverse hyper conjugation because in CF3 the bond is very strong CF bond is very strong difficult to break okay another point is what in CBR3 and CI3 as the electronegativity decreases for bromine and iodine it is difficult to break this CBR bond okay size increasing bond becomes less polar in that case right is most electronegative right so polar bond will be there but the bond length is minimum so this bond is difficult to break right CCN3 the electronegativity is there for chlorine atom so bond is more polar than these two and bond length is also more than this so here is carbon chlorine bond you can break but here the bond length increases but polarity is not there that's why in CBR3 and CI3 bond is not polar this is the carbon bromine or carbon iodine bond is difficult to break that's why out of this four molecule only CCN3 shows minus H or reverse hyper conjugation okay logic if you understand fine otherwise CCN3 what did I say this is non polar non polar difficult to break polar but bond length is minimum again difficult right CCN3 it's polar also and bond length is more than CF so we can break this right so now when you draw the structure into this the hyper conjugative structure of minus H effect it goes like this first we have this council if we draw one council over here and this is taken by this pi converts into this pi converts into pi here and this sigma converts into lone pair okay so this gives you this bond will be as it is here we have positive ccl negative cl and c4 further you can draw the structure so then that the this one will also yes in this resonating structure you can draw so you get positive charge plus first year and then it comes over your positive charge yes we will have so here also you see because of electrons sorry minus H effect the electron density decreases at ortho and para position right now because of minus H effect electron density decreases at ortho and para position because of minus H effect electron density decreases at ortho and para position okay the most important point is at ortho and para position we have hyper conjugation possible any group which is attached at ortho and para position can show hyper conjugation or can show mesoameric okay now you write on compare the electron density at ortho and para position compare the electron density at ortho and para position in this molecule cx3 compare the electron density at ortho and para position one more example done I will write on one more then you tell me a v c d a v c tell me decreasing order a c I don't know words not right oh I will tell you one thing this shows what effect see for this kind of question whether you have to you know find out in this kind of question whether you have to find out the stability of the compound intermediate or acidity order basically order first of all you have to identify what effect the group shows right so what effect this group shows plus plus but which one is dominating plus in the number of effects if they ask both plus plus here what effect we have minus I possible plus but again minus okay here what happens minus and minus there is no plus minus we have a multiple bond so nothing but this and this attached with the ring you see this is a conjugation right so and it shows minus m okay which one is dominating minus i or minus m minus m minus m dominates okay O C S 3 minus i n plus m da how it is minus m because we have double pair on this oxygen so first item man has lone pair how it will happen you have to do it if you have to decide how to do it again one basic thing you have to memorize the atom with which the ring is attached if the atom contains at least one lone pair it shows plus m effect only then you will release the electron only then you will release the ring okay all basics are logical and upto here we have a double bond this comes over here this goes over here when rocker okay now the dominating effect is plus m obviously plus minus m here minus h here and plus so plus h increases electron density or decreases at ortho and para position increases plus m increases or decreases or increase this comes over here and then this comes over here okay okay so all these plus effect all these plus effect increases electron density at ortho and para position okay minus effect decreases electron density at ortho and para position okay now wait wait plus h will increase plus m will also increase which one will increase more plus m plus h plus m dominates hyper conjugation resonance dominates hyper conjugation and then i so plus m dominates m in this resonance only so plus m is most dominating plus m dominates plus h plus h dominates plus i or minus i whatever it is so plus m will increase the electron density maximum here so order will be what? it is maximum for d then we have plus h which is a and then here we have minus h here we have minus m so minus m will decrease minus h will also decrease but this will decrease more this will have more effect so it is b how many of you understood this? this was the first question when we solve we will do many questions you will understand that only one thing you keep in mind whatever group is attached first of all you identify the effect of that group and then accordingly okay understood this is it clear this one? okay in this one you tell me where we have more electron density so like first you identify the effect ccl3s are all minus h okay so this one is minus h5 so but then all both of them are minus h and minus h will increase what? increase of positive charge at orbital and para position here what effect we have? minus h minus m minus i minus m how? minus m is not there minus m minus h because this carbon does not have carbon has carbon and this carbon has thing loading we have carbon carbon bond carbon carbon bond if I write down here c cl3 then it is fine like this one so here we have minus i here we have minus h minus i because you see this molecule is not carbon chlorine bond is not there if it is there then this comes over here this goes under this chlorine bond but what we have? we have carbon carbon bond and this carbon has 3 chlorine so this cannot take this electron minus h is not possible clear right but this chlorine has minus i effect overall this group shows what? minus i effect this drags electron from this carbon this carbon from this carbon and this carbon from this ring so here we have minus i effect now minus i will increase positive charge density at what? ortho position which one has more effect? minus i this will increase electron density will be more in the positive understood electron density will be more here however we have positive charge here but comparatively here we will have less positive charge so more electron density understood ok we will take a break ok ok ok ok ok ok ok ok ok