 Hello and welcome to the session. I am Deepika here. Let's discuss a question. Find the value of the following cos inverse 1 by 2 plus 2 sin inverse 1 by 2. So let's start the solution for principle value of cos inverse 1 by 2. So we have of cos inverse 1 by 2 is equal to pi by 3 because the range of closed intervals 0 to pi and equal to 1 by 2. Therefore, the value of cos inverse 1 by 2 is equal to pi by 3. Similarly, we will find the value of sin inverse 1 by 2. So the principle value of sin inverse 1 by 2 is equal to pi by 6 because the range of minus pi by 2 to pi by 2 is equal to of sin inverse 1 by 2 is equal to pi by 6. Now, therefore, the value of cos inverse by 6. So we have this is this is equal to pi by 3 plus pi by 3 which is equal to 2 pi by 3. Therefore, the value of cos inverse 1 by 2 plus 2 sin inverse 1 by 2 is 2 pi by 3 and this is our answer for the above question. I hope the question is clear to you. Bye and enjoy yourself.