 Hello and welcome to this session. Let us understand the following problem today. Find value of k if area of triangle is 4 square units and vertices are minus 2 comma 0, 0 comma 4 and 0 comma k. Now let us write the solution. When vertices of a triangle are given, then area of triangle A, B, C is given by half into determinant of minus 2, 0, 1, 0, 4, 1 and 0, k, 1. Now which I am solving we get half into minus 2 into 4 minus k minus 0 plus 1 into 0 minus 0 which implies half into minus 8 plus 2 k. Now taking 2 common we get k minus 4. So given to us area is equal to plus minus 4. Now when area is equal to plus 4 we get 4 is equal to k minus 4 which implies k is equal to 8. Now when area is equal to minus 4 then minus 4 is equal to k minus 4 which implies k is equal to 0. Therefore required values of k are 0 comma 8. I hope you understood the problem bye and have a nice day.