 Hi and welcome to the session, I am Deepika here. Let's discuss a question, differentiate the following with respect to x. Log of log x, where x is greater than 1. Let's start the solution. Let y is equal to log of log x where x is greater than 1. Therefore dy by dx is equal to now derivative of log x is 1 over x therefore derivative of log of log x is equal to 1 over log x into derivative of log x that is into 1 over x. So this is equal to dy by dx is equal to 1 over x log x where x is greater than 1. Hence the answer for the above question is dy by dx is equal to 1 over x log x where x is greater than 1. Hence this is the answer for the above question. I hope the question is clear to you, why and take care.