 Hello and welcome to the session. Let us discuss the following problem today. Find the zeroes of the foreign quadratic polynomial and verify the relationship between the zeroes and the coefficients. We have f of u is equal to 4u square plus a2. So, we have f of u is equal to 4u square plus a2. Now, solving this, we take 4u common. So, we are left with u plus 2. Now, we know zeroes of f of u are given by f of u is equal to 0. Therefore, f of u is equal to 0, which implies 4u into u plus 2 is equal to 0, which implies 4u is equal to 0 or u plus 2 is equal to 0, which implies u is equal to 0 or u is equal to minus 2. Zeroes of f of u are alpha is equal to 0 and beta is equal to minus 2. Now, the verification part, sum of zeroes, that is alpha plus beta is equal to 0 plus minus 2, which is equal to minus 2, that is coefficient of u by coefficient of u square, which is equal to minus 8 by 4, which is equal to minus 2. Similarly, product of zeroes, that is alpha beta is equal to 0 into minus 2, that is equal to 0, that is constant term divided by coefficient of u square, which is equal to 0 by 4, which is equal to 0. Hence, verify it. Hope you understood the problem. Bye and have a nice day.