 Write down the last few things they have to discuss here. Nomenclature of the spiral compounds. Write down, write down nomenclature of the spiral compounds. The spiral compounds are the compounds in which spiral compounds are the compounds in which two rings are attached together two rings are attached together with a quaternary carbon atom quaternary carbon, four degree, carbon attached with four carbon atoms quaternary carbon atom for example you see this if you have a ring it is a spiral compound it is a spiral compound because the two rings which is the four member ring this one cyclobutane and cyclopropane attached with one common carbon atom quaternary because this carbon attached with four carbon atoms we have this rule that will follow not that important just we will see some examples ok so to write down the name of us so how can that carbon do this not equal to anything we have to do no if you have two cyclopropane attached together in this it is possible ok that compound is bicycle compound ok now to write down the name not to write down the name of this compound we will use prefix spiral ok spiral and then we will write down this bracket and in the bracket we will write down the number the number of carbon atoms present in the two ring in ascending order excluding the common carbon atom so what we will do here this carbon atom we will let it be we have to number the carbon atom in this ring ok so this carbon you let it be we will start the numbering from the lower ring this is one and this is two right all these are roles now maybe we should start from the smaller ring right one two then this this carbon will be third and now we can write down this as fourth this as fourth these two positions are equivalent positions any one of these two carbon you can take as the fourth carbon but if you have any substituents present here then we have to bound to give this as fourth position ok so this is three this one is four this one is five this one is six like this we told that so what are two substituents? see that we will take the example have some patience understood sir sir sir sir no we don't have to do it from the heart no ok so the rule is what when the two rings are attached to the one common carbon atom it is a spiral compound spiral compounds we have rules ok so one two exclude this carbon atom we have two carbon here we have two carbon here and three carbon here right how many total number of carbon atoms are what? total number of carbon atoms are six right so we will write here this two two carbon atoms here and three carbon atoms here two dot three don't write comma here right two dot three total number of carbon atom is six that is this carbon here attached to it how many carbon atoms in this way? two one and two two carbon atoms here and three carbon atoms here two dot three this number we always write in ascending order sir what do we have to do? so three dot two we want to write compound is possible but name is written three dot two is wrong this is how we write it three dot two two dot three we cannot write three dot two we cannot write three dot that is not entertaining it must be ascending order if you have three of them like you have one more thing to do and that is three then that will become the substance we have to see it like this if you have one more and write it down five one more and write this one more and write this right so this will take this will take and this becomes the substance where is the substance? where then we will ask the poisoner even then there won't be no if the one more is there then this two is the substance this two is the substance but you won't get more than two ring in a compound I haven't seen this yet but if it is there one becomes the substance other two will take less than so the one with more number is me if any functional group is not there understood this write down the name of this compound this one let's say no attach to it sir you drew one yeah no I am trying to take the maximum number of carbon atoms so there we start from the middle we have only two we have to start from the smaller one so in this two this is the smaller one in this two this is the smaller one so in those two so this won't give you the longest change one two three four five six seven one two three four five six seven eight okay so we are taking two S side six cyclopropyl three dot five first side is pyro three dot five octane three dot one two three three dot four three dot four six cyclopropyl octane sir how do you know how to this one this one see we always start for this year we always start from this smaller ring and this carbon we won't give this carbon the first carbon the common carbon this is one this is two then it is three four five six so I know three comma five three comma four one two three three comma four three dot four three dot four six cyclopropyl octane no write down the name of this compound one more one more one more one more is it one more one more one more one more one more one more one more four one more two one more one more one more one more five four five five So, what was it? It was all pink. So, it's all pink. Except pink. Except pink. Except pink. Everyone in your mind. So, you did the half of all of it. You did that. You did that first. That's all pink. That's all pink. That's all pink. That's all pink. That's all pink. So, The last one right now, bi-cyclocompound. Right on, when the two rings are joined together by two carbon atoms, when the two rings are joined together by two carbon atoms, then the compound is known as bi-cyclocompound. For example, you see, okay, this is bi-cyclocompound. These two carbons are carbon atoms. This is these two carbons are bridge head carbons. This is two carbon bridge. This is also two carbon bridge. And this one is one carbon bridge. Now, is this what we have to do? Suppose we have to number this carbon, name this carbon at molecule, we'll start numbering from the bridge head carbon. This carbon will start numbering. For example, you'll see, I'll write down this example now. We have this molecule. Okay, this molecule. So we'll start numbering from the bridge head carbon, this carbon atom. How many carbon atom bridge we have? This side we have three carbon bridge. This side we have four carbon bridge. And here we have, there's no carbon present here. So we'll start numbering from this carbon atom one. And there we are going towards the smaller ring. Here we'll go towards the larger ring. Just reverse of that. We have to start from here. Larger ring is this ring. So one, two, three, four, five, six, seven, eight and nine. Okay. We'll start from the bridge head carbon. And then towards the larger ring. Name of this compound is bicyclo, okay. In this bracket, we'll write down the number of carbon atom in the bridge. Okay, and that will be in descending order. There we have in descending order, here we have in descending order. So here we have four carbon atom, three carbon atom, and here we have zero. Right? So we'll write four dot, three dot, zero. Because this is one. If this bond will write down this way, then four dot, dot eight, dot three, dot one here. But here we do not have any carbon atom. The bridge head carbon are joined together directly like this. If the bridge head carbon are joined together by any carbon atom, then that carbon atom will write down. Okay. Right. So four dot, three dot, zero. The number of that carbon atom is seven. If there was a number of the carbon atom at the end of the bridge would be seven. Tenth one. We'll do ring and last one. Like in this case it will be one, two, three, four, five, six and seven. Okay. So for this one the name will be what? Bicyclo? No. Two dot, two dot one. Ten. So carbon six and seven are not connected. Yes. We'll number this carbon atom in the last one. So, it's just that it's a two carbon bond. So, why would it work? Cyclo- No, I have written this, in this way. Actually, we have this two rings. What's the ring? This ring. And we have one ring in this. It is two rings, actually. I've written this one. You can do it. I've written this one. You can do the two rings. You see, one ring is the cyclo-dixie. And wondering is this, what these two carbon atoms, like just come to see here, these two carbon atoms. Sir, enjoy. You see, you see, you know, here is this, cyclopentane, cycloxane, these two carbon atoms are common. Sir, if we had to say, bend in both the groups. Because in both three carbon atoms, they come in this. In both three carbon atoms. No, no, we are separating this to this way. Like, to make you understand. But actually, you see, if we have this ring and this ring, we are taking, you see, we are taking this carbon atom, you know, in the square branch. This one, this one, this one, it is just the cyclopentane, cycloxane, cyclopentane, cyclopentane, cyclopentane, cyclopentane, cyclopentane, cyclopentane. No, you can, again, take this, this way, also, inside, inside and above, coming up. Right? But when you, when you define this as a y-cyclo, the part, then you must want to understand how the two rings are attached. And then, when we try to separate this, we get this kind of structure. But since two carbon atoms are common here. Right, so it is y-cyclo. Here also, you see, see, to separate this, we get this, this, and this one. Two carbon atoms. So say, the two, five, eight, and nine and seven had a frame, what do we name it? Two, five, two, five, nine and seven had the same frame. Then you have four sides. You have four sides. Wait, I'll draw. Four, I didn't have to draw. Oh god. They said two, I didn't have to draw. They even know who is the king. This is a two-brin star. No point of being called a star. So what is the correct answer to this? Five. It's a little bit more complicated. Okay this one, what is the name? Five. Five side four. Two dot two dot two dot two dot. I don't know. Oh god. No. Sir, what is the structure of the structure? 2 dot, 2 dot, 0, xx Yeah This one bi-cyclot 2 dot, 2 dot, 2 Okay! No way! No way, sir! Yeah, it is one Like it is in the backside It's towards you This is behind you Yeah, it's on It's in the middle But it's not the car right? This is This is behind you It's not the car I'm not feeling that much Sir, what exactly should be 1 and 4 is this Sir, how is that 7 and 8? Which one? 1, 2, 3, 4, 5, 6 There's an half to 6 7 and 8 It shouldn't be that way It is not the carbon atom This compound is like this 2 carbon and 2 carbon And here also we have 2 carbon atom 3 damage associated Yes sir, I had in mind It is going from behind the road It's not interesting Take care 2 carbon bridge 2 carbon bridge 4, 4, 9, 8 bi-cyclot 2 dot, 2 dot, 2 Okay! So where is this? We take a break This is your copy done. This one I already know. Yes.