 Hi, welcome to the session. Let's discuss the question. The number of all possible matrices of order 3 by 3 with each entry 0 or 1 is A 27, B 18, C 81, D 512. Let's start the solution. Since total number of elements in the matrix of order m by n is equal to m multiplied by m, which is equal to mn element, therefore total number of elements in a matrix of order 3 by 3, 3 by 3 is equal to 3 into 3, which is equal to 9. Now for each of elements, there are two options to be filled, either 0 or 1. Therefore total number of different matrices is equal to 2 into 2 up to 9 times, which is equal to 2 raised to power 9 or 512. Therefore the number of all possible matrices of order 3 by 3 with each entry 0 or 1 is 512. Hence our option D is correct, that is D is the answer. Hope you have understood the question. Bye and have a good day.