 Hello and welcome to the session. Let us construct a triangle x, y, z in which angle y is 30 degrees and the z is 90 degrees and the sum of three sides is 11 centimeters. To construct the required triangle, we will follow the steps of construction 11.6 which says to construct the triangle given as a perimeter and it is two base angles. So here we have given two base angles and the sum of three sides that is the perimeter triangle x, y, z. So first let us draw a rough figure of how we are going to construct the triangle. First we shall draw a line segment AB which has the sum of three sides of the triangle which we said there is 11 centimeters. Then we shall construct angle LAB 30 degrees equal to 90 degrees. Now we shall bisect both of these angles. Suppose we shall bisect it with the help of a compass. Here we are just drawing it roughly. Suppose by bisecting the point of intersection let us call it as we shall draw the perpendicular bisectors, line segment XA, line segment XP. The point of intersection of the perpendicular bisectors is named as Y and Z. Then we shall join XY, XZ to get the required triangle XYZ. So this is the required triangle XYZ such that its perimeter is 11 centimeters and angle Y is 30 degrees and angle Z is 90 degrees. Now let us write the steps of construction and side by side. Let us draw the figure also with the help of geometrical instruments. First segment AB is equal to 11 centimeters which is the perimeter of the required triangle. Now next step is to construct angle LAB is equal to 30 degrees and angle MBA is equal to 90 degrees. Then in the third step bisect angle LAB and angle MBA and let these bisectors, bisector of angle MBA get the point of intersection B and bisectors segment AB require triangle, require triangle. So this completes the solution. Hope you have enjoyed it. Take care and have a good day.