 Hello and welcome to the session. I am Deepika here. Let's discuss a question which says the length of the minute hand of a clock is 14 centimeter. Find the area trapped by the minute hand in five minutes. Now this problem is based on the area of a sector of a circle. Now we know the formula for area of the triangle theta which is given by theta upon 360 into pi r square where r is the radius sector in degrees. So this is a key idea behind our question. We will take the help of this key idea to solve the above question. So let's start the solution. Now we have given the length of the minute hand of a clock 14 centimeter that is radius is equal to 14 centimeter. Now we know that the minute hand makes one revolution in 60 minutes that is minute hand makes an angle of 360 degree in 60 minutes. The area swept by the minute hand in five minutes by the minute hand in five minutes by the minute hand is equal to 360. So in one minute by minute hand is equal to 360 upon 60. Five minutes angle made by minute hand is equal to 360 upon 60 into five. So on cancellation we have in five minutes the angle made by the minute hand is 30 that is theta minute hand 30 degree equal to 14 centimeter. The idea area of the sector of angle theta is equal to 360 into pi r square is equal to theta is 30 60 into take pi as 22 by 7 14 centimeter square. So on cancellation we have 11 into 14 centimeter square or this is equal to 154 upon 3 centimeter square. Hence the answer for the above question is 154 upon 3 centimeter square. I hope the solution is clear to you. Bye and take care.