 Hi and welcome to the session. Let's work out the following question. The question says find a point on x axis which is equidistant from the points 7, 6 and minus 3, 4. So let us start with the solution to this question. Let the point be 7, 6 and the point q minus 3, 4 and the point s say x 0 because we have to find a point on x axis only y or we can say that let p, q and s be the points on x axis. Now it's given to us in the question that p s is equal to q s because distance between the point p and the point s is equal to the distance between the point q and the point s. Therefore, we have square root of x minus minus 3 the whole square plus 0 minus 4 the whole square is equal to square root of x minus 7 the whole square plus 0 minus 6 the whole square or we can say that square root of x plus 3 the whole square plus 16 is equal to square root of x minus 7 the whole square plus 36 or now we can square both the sides and we have x plus 3 the whole square plus 16 is equal to x minus 7 the whole square plus 36 or this can be written as x plus 3 the whole square minus x minus 7 the whole square is equal to 36 minus 16 or this can be written as x square plus 6 x plus 9 minus x square minus 14 x plus 49 is equal to 20 or x square plus 6 x plus 9 minus x square plus 14 x minus 49 is equal to 20 or 20 x minus 40 is equal to 20 or 20 x is equal to 60 or x is equal to 60 divided by 20 that is equal to 3. Therefore, the coordinates of s is 3 0. So, this is our answer to this question. I hope that you understood the solution and enjoyed the session. Have a good day.